The approximate pH of seawater is 8.5 . Calculate the pOH , the \( \left[\mathrm{H}^{+}\right] \), and the \( \left[\mathrm{OH}^{-}\right] \). \( \left[\mathrm{HOH}^{+}\right]=\square \) \( \left[\mathrm{OH}^{-}\right]=\square \)

To find the pOH from the given pH of seawater, you can use the relationship: pOH = 14 - pH. So, pOH = 14 - 8.5 = 5.5. Next, to calculate the hydrogen ion concentration \( \left[\mathrm{H}^{+}\right] \): \( \left[\mathrm{H}^{+}\right] = 10^{-\text{pH}} = 10^{-8.5} \approx 3.16 \times 10^{-9} \, \text{M} \). Then, for the hydroxide ion concentration \( \left[\mathrm{OH}^{-}\right] \): \( \left[\mathrm{OH}^{-}\right] = 10^{-\text{pOH}} = 10^{-5.5} \approx 3.16 \times 10^{-6} \, \text{M} \). Thus, the values are: \( \left[\mathrm{H}^{+}\right] \approx 3.16 \times 10^{-9} \, \text{M} \) \( \left[\mathrm{OH}^{-}\right] \approx 3.16 \times 10^{-6} \, \text{M} \)