Phyllis invested \( \$ 50,000 \) in two different types of stock. The first type earned \( 10 \% \) and the second type earned \( 15 \% \). If the profit on the the \( 10 \% \) stock, how much did Phyllis invest in the \( 15 \% \) stock?

It appears there's a small typo in your problem statement. Assuming you meant to say that **the profit from the 10% stock is equal to the profit from the 15% stock**, we can solve the problem as follows: **Let:** - \( x \) be the amount invested in the 10% stock. - \( \$50,000 - x \) be the amount invested in the 15% stock. **Given:** - Profit from 10% stock: \( 0.10x \) - Profit from 15% stock: \( 0.15(\$50,000 - x) \) - Profits are equal: \( 0.10x = 0.15(\$50,000 - x) \) **Set Up the Equation:** \[ 0.10x = 0.15(\$50,000 - x) \] **Solve for \( x \):** \[ 0.10x = \$7,500 - 0.15x \] \[ 0.10x + 0.15x = \$7,500 \] \[ 0.25x = \$7,500 \] \[ x = \frac{\$7,500}{0.25} = \$30,000 \] **Amount Invested in the 15% Stock:** \[ \$50,000 - \$30,000 = \$20,000 \] **Answer:** Phyllis invested **\$20,000** in the 15% stock.