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5. Given that \( \sin \theta>0 \) and that \( \cot \theta=\frac{7}{5} \), find the other five trig functions. Sin theta \( =5 / \operatorname{sqrt} 74, \cos \) theta \( =7 / \) sqrt 74 , tan theta \( =5 / 7 \), csc theta \( = \) frac/sqrt 74 \( a^{\wedge} 2+b^{\wedge} 2=c^{\wedge} 2 \)

Ask by Bradley Joseph. in the United States
Jan 20,2025

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\[ \sin \theta = \frac{5}{\sqrt{74}}, \quad \cos \theta = \frac{7}{\sqrt{74}}, \quad \tan \theta = \frac{5}{7}, \quad \csc \theta = \frac{\sqrt{74}}{5}, \quad \sec \theta = \frac{\sqrt{74}}{7}, \quad \cot \theta = \frac{7}{5} \]

Solution

To find the other five trigonometric functions given that \( \sin \theta > 0 \) and \( \cot \theta = \frac{7}{5} \), we can follow these steps: 1. **Understanding Cotangent**: \[ \cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{7}{5} \] This means that for every 7 units of the adjacent side (cosine), there are 5 units of the opposite side (sine) in a right triangle. 2. **Finding Sine and Cosine**: We can use the Pythagorean theorem to find the hypotenuse. The sides of the triangle are: - Opposite side (for sine): \( 5 \) - Adjacent side (for cosine): \( 7 \) The hypotenuse \( h \) can be calculated as: \[ h = \sqrt{(5^2 + 7^2)} = \sqrt{25 + 49} = \sqrt{74} \] Now we can find sine and cosine: \[ \sin \theta = \frac{5}{\sqrt{74}}, \quad \cos \theta = \frac{7}{\sqrt{74}} \] 3. **Finding Tangent**: Tangent is the ratio of sine to cosine: \[ \tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{5/\sqrt{74}}{7/\sqrt{74}} = \frac{5}{7} \] 4. **Finding Cosecant**: Cosecant is the reciprocal of sine: \[ \csc \theta = \frac{1}{\sin \theta} = \frac{\sqrt{74}}{5} \] 5. **Finding Secant**: Secant is the reciprocal of cosine: \[ \sec \theta = \frac{1}{\cos \theta} = \frac{\sqrt{74}}{7} \] 6. **Finding Cotangent**: Cotangent is already given as: \[ \cot \theta = \frac{7}{5} \] Now we have all six trigonometric functions: - \( \sin \theta = \frac{5}{\sqrt{74}} \) - \( \cos \theta = \frac{7}{\sqrt{74}} \) - \( \tan \theta = \frac{5}{7} \) - \( \csc \theta = \frac{\sqrt{74}}{5} \) - \( \sec \theta = \frac{\sqrt{74}}{7} \) - \( \cot \theta = \frac{7}{5} \) Thus, the final results are: - \( \sin \theta = \frac{5}{\sqrt{74}} \) - \( \cos \theta = \frac{7}{\sqrt{74}} \) - \( \tan \theta = \frac{5}{7} \) - \( \csc \theta = \frac{\sqrt{74}}{5} \) - \( \sec \theta = \frac{\sqrt{74}}{7} \) - \( \cot \theta = \frac{7}{5} \)

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Did you know that the relationship between the trigonometric functions can be traced back to ancient civilizations? The Egyptians and Babylonians used rudimentary forms of trigonometry over 4,000 years ago to help build their monuments and navigate the heavens. They primarily focused on right triangles and the ratios of their sides, just like the relationships we explore with sine, cosine, and tangent today! For practical applications, trigonometric functions are crucial in fields ranging from engineering to computer graphics. For example, in engineering, they are used to determine forces in structures and to model wave patterns. In computer graphics, sine and cosine functions generate smooth periodic movements and animations. Whether you're programming a video game or designing a bridge, understanding these functions is key!

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