Balance this equation. CCF \( _{4+}^{+} \mathrm{Br}_{2}-->\mathrm{CBr}_{4}^{+} \)

To balance the equation CCF \( _{4+}^{+} \mathrm{Br}_{2} \rightarrow \mathrm{CBr}_{4}^{+} \), ensure that the same number of atoms appears on both sides. On the left, you have one carbon atom and four fluorine atoms along with two bromine atoms. On the right, with CBr₄, you have one carbon and four bromine atoms, but no fluorine is present on the right. Therefore, you can balance the equation by making sure the number of atoms is the same on each side: The balanced equation would be: CCF \( _{4+}^{+} \mathrm{Br}_{2} \rightarrow \mathrm{CBr}_{4}^{+} + 4\mathrm{F} \) (considering the four fluorine atoms would leave the compound to balance the charge). Adjust the products as needed to maintain charge balance while preserving the element counts. This showcases how chemical reactions also focus on the conservation of mass and charge!