Question

2 Jutian is comparing the fuel economy of two different cars in city driving. Car A uses fuel at the rate of \( 6.9 \mathrm{~L} / 100 \mathrm{~km} \) while Car B uses fuel at \( 7.8 \mathrm{~L} / 100 \mathrm{~km} \). Jutian averages 820 km of city driving each month. How much less fuel will he use in one year driving Car A instead of Car B? (A) 7.38 L (B) 73.8 L (C) 88.56 L (1) 738 L

Ask by Hilton Elliott. in Iran
Jan 11,2025

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Jutian will save 88.56 liters of fuel in one year by driving Car A instead of Car B.

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To find out how much less fuel Jutian will use in one year driving Car A instead of Car B, we first need to calculate the total fuel consumption for each car over the year based on the monthly average driving distance. 1. **Monthly Fuel Consumption:** - For Car A: \[ \text{Monthly Consumption} = \frac{6.9 \text{ L}}{100 \text{ km}} \times 820 \text{ km} = 56.58 \text{ L} \] - For Car B: \[ \text{Monthly Consumption} = \frac{7.8 \text{ L}}{100 \text{ km}} \times 820 \text{ km} = 63.96 \text{ L} \] 2. **Yearly Fuel Consumption:** - For Car A: \[ \text{Yearly Consumption} = 56.58 \text{ L/month} \times 12 \text{ months} = 678.96 \text{ L} \] - For Car B: \[ \text{Yearly Consumption} = 63.96 \text{ L/month} \times 12 \text{ months} = 767.52 \text{ L} \] 3. **Difference in Fuel Consumption:** \[ \text{Fuel Saving} = 767.52 \text{ L} - 678.96 \text{ L} = 88.56 \text{ L} \] So, the answer is (C) 88.56 L.

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