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12. Write a polynomial in factored form with zeros \( 5,6,7 \) and \( a=1 \)

Ask by Vega Dunn. in the United States
Jan 23,2025

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Answer

One such polynomial is \( (x - 5)(x - 6)(x - 7) \).

Solution

To construct a polynomial in factored form with the given zeros \( 5, 6, 7 \) and a leading coefficient \( a = 1 \), you can use the fact that each zero corresponds to a factor of the polynomial. Specifically, a zero at \( x = c \) corresponds to a factor of \( (x - c) \). Given zeros at \( x = 5 \), \( x = 6 \), and \( x = 7 \), the polynomial can be written as: \[ f(x) = 1 \cdot (x - 5)(x - 6)(x - 7) \] Since the leading coefficient \( a = 1 \), it is often omitted for simplicity. Therefore, the polynomial in its simplest factored form is: \[ f(x) = (x - 5)(x - 6)(x - 7) \] **Final Answer:** After simplifying, one such polynomial is (x – 5) (x – 6) (x – 7).

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Extra Insights

To write a polynomial in factored form with zeros at \( 5, 6, \) and \( 7 \), you can use the fact that the polynomial can be expressed as \( (x - 5)(x - 6)(x - 7) \). Since \( a = 1 \), you don’t need to include any additional coefficients. So, the polynomial is: \[ f(x) = (x - 5)(x - 6)(x - 7) \] If you expand this, you’ll end up with a cubic polynomial, but in this case, we’re celebrating the beauty of the factored form! An interesting aspect of polynomials is how they relate to the shapes of their graphs. Since we have three distinct zeros, the graph of this polynomial will intersect the x-axis at the points \( 5, 6, \) and \( 7 \). Each zero corresponds to a "bounce" or "pass-through" at the x-axis, giving your polynomial a distinct shape and a chance for some creative interpretation if you're into sketching!

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