Question
\( \left. \begin{array} { l l } { - 5 \cdot ( - 6 x ^ { 2 } ) } & { - 6 x - ( + 7 x ) } \\ { - 2 a ^ { 3 } \cdot ( - 4 a ) } & { + 10 a \cdot ( - a ^ { 4 } ) } \\ { - 8 \cdot ( - 5 x ) } & { - a b - ( - 2 a ) } \\ { - 5 a \cdot ( - 4 a ^ { 2 } ) } & { - 8 a ^ { 2 } - ( - 3 a ^ { 4 } ) } \end{array} \right. \)
Ask by Schneider Gray. in Italy
Jan 23,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
Ecco le espressioni semplificate:
1.
\[
-5 \cdot (-6x^2) = 30x^2
\]
\[
-6x - (+7x) = -13x
\]
2.
\[
-2a^3 \cdot (-4a) = 8a^4
\]
\[
10a \cdot (-a^4) = -10a^5
\]
3.
\[
-8 \cdot (-5x) = 40x
\]
\[
-ab - (-2a) = -ab + 2a
\]
4.
\[
-5a \cdot (-4a^2) = 20a^3
\]
\[
-8a^2 - (-3a^4) = 3a^4 - 8a^2
\]
Solution
Ecco le espressioni semplificate:
1.
\[
-5 \cdot (-6x^2) = 30x^2
\]
\[
-6x - (+7x) = -13x
\]
2.
\[
-2a^3 \cdot (-4a) = 8a^4
\]
\[
10a \cdot (-a^4) = -10a^5
\]
3.
\[
-8 \cdot (-5x) = 40x
\]
\[
-ab - (-2a) = -ab + 2a
\]
4.
\[
-5a \cdot (-4a^2) = 20a^3
\]
\[
-8a^2 - (-3a^4) = 3a^4 - 8a^2
\]
Reviewed and approved by the UpStudy tutoring team
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Simplify this solution The Deep Dive
Let's break down those expressions into more manageable chunks, shall we? For the first set, \(-5 \cdot (-6x^2)\) equals \(30x^2\) and \(-6x - (+7x)\) combines to \(-13x\). Moving on to the second pair, \(-2a^3 \cdot (-4a)\) simplifies to \(8a^4\) and \(+10a \cdot (-a^4)\) results in \(-10a^5\). Next, \(-8 \cdot (-5x)\) gives \(40x\) while \(-ab - (-2a)\) simplifies to \(2a - ab\). Finally, \(-5a \cdot (-4a^2)\) leads to \(20a^3\) and \(-8a^2 - (-3a^4)\) becomes \(3a^4 - 8a^2\). Now you’re all set for some exciting algebra practice!
