Question
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A line has a slope of -3 and passes through the point \( (4,-15) \). Write its equation in slope- intercept form. Write your answer using integers, proper fractions, and improper fractions in simplest form.

Ask by Schofield Adkins. in the United States
Jan 24,2025

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Tutor-Verified Answer

Answer

The equation of the line in slope-intercept form is \( y = -3x - 3 \).

Solution

The slope-intercept form of a line is given by: \[ y = mx + b \] where \( m \) is the slope and \( b \) is the y-intercept. Given: - Slope (\( m \)) = -3 - The line passes through the point \( (4, -15) \). First, substitute the slope and the coordinates of the point into the equation to solve for \( b \): \[ -15 = (-3)(4) + b \] \[ -15 = -12 + b \] \[ b = -15 + 12 \] \[ b = -3 \] So, the equation of the line in slope-intercept form is: \[ y = -3x - 3 \] **Answer:** \( y = -3x - 3 \)

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The Deep Dive

To find the equation of the line in slope-intercept form \( y = mx + b \), we start with the given slope \( m = -3 \) and the point \( (4, -15) \). We can substitute these values into the equation to find \( b \): \[ -15 = -3(4) + b \] \[ -15 = -12 + b \] \[ b = -15 + 12 = -3 \] Now we can write the equation of the line: \[ y = -3x - 3 \] So, the equation in slope-intercept form is \( y = -3x - 3 \).

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