Which of the following integers is least? $$ \begin{array}{l} ext { (1) }-5+(-2) \ ext { O } \ ext { O }-5 \div(-2) \ ext { O } \ ext { D }-5 imes(-2)\end{array} $$

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Which of the following integers is least? $$ \begin{array}{l}	ext { (1) }-5+(-2) \ 	ext { O } \ 	ext { O }-5 \div(-2) \ 	ext { O } \ 	ext { D }-5 	imes(-2)\end{array} $$

UpStudy AI · Accepted Answer

Calculate the value by following steps:
- step0: Calculate:
  $$-5\left(-2\right)$$
- step1: Use the rules for multiplication and division:
  $$5\times 2$$
- step2: Multiply the numbers:
  $$10$$
Calculate or simplify the expression $$ -5+(-2) $$.
Calculate the value by following steps:
- step0: Calculate:
  $$-5+\left(-2\right)$$
- step1: Remove the parentheses:
  $$-5-2$$
- step2: Subtract the numbers:
  $$-7$$
Calculate or simplify the expression $$ -5/(-2) $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{-5}{\left(-2\right)}$$
- step1: Remove the parentheses:
  $$\frac{-5}{-2}$$
- step2: Reduce the fraction:
  $$\frac{5}{2}$$
Let's evaluate each expression step by step:

1. **For the expression $$-5 + (-2)$$**:
   $$
   -5 + (-2) = -5 - 2 = -7
   $$

2. **For the expression $$-5 \div (-2)$$**:
   $$
   -5 \div (-2) = \frac{5}{2} = 2.5
   $$

3. **For the expression $$-5 \times (-2)$$**:
   $$
   -5 \times (-2) = 10
   $$

Now we have the results:
- $$ -5 + (-2) = -7 $$
- $$ -5 \div (-2) = 2.5 $$
- $$ -5 \times (-2) = 10 $$

Among these integers, the least is $$-7$$.

Thus, the least integer is:
$$
\boxed{-7}
$$
The least integer is -7.

Which of the following integers is least? \( \begin{array}{l}\text { (1) }-5+(-2) \\ \text { O } \\ \text { O }-5 \div(-2) \\ \text { O } \\ \text { D }-5 \times(-2)\end{array} \)

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