olve the following quadratic function by utilizing the square root method. \[ \begin{array}{l}y=x^{2}-9 \\ x= \pm[?]\end{array} \]

To solve the quadratic function \( y = x^2 - 9 \) using the square root method, we first set \( y = 0 \): \[ 0 = x^2 - 9 \] Next, we add 9 to both sides: \[ x^2 = 9 \] Now, we take the square root of both sides, remembering to include both the positive and negative roots: \[ x = \pm \sqrt{9} \] Thus, we find: \[ x = \pm 3 \] So the solutions for the quadratic function are \( x = 3 \) and \( x = -3 \).