\( \begin{array}{lll}\text { 1. }\left(5 \frac{1}{2}+2 \frac{3}{4}\right)-3 \frac{1}{2} & \text { 2. } 10\end{array} \)

Sure, I'd be happy to help you solve these problems! --- ### **Problem 1** \[ \left(5 \frac{1}{2} + 2 \frac{3}{4}\right) - 3 \frac{1}{2} \] **Step 1: Convert Mixed Numbers to Improper Fractions** 1. **\(5 \frac{1}{2}\)** \[ 5 \frac{1}{2} = \frac{5 \times 2 + 1}{2} = \frac{10 + 1}{2} = \frac{11}{2} \] 2. **\(2 \frac{3}{4}\)** \[ 2 \frac{3}{4} = \frac{2 \times 4 + 3}{4} = \frac{8 + 3}{4} = \frac{11}{4} \] 3. **\(3 \frac{1}{2}\)** \[ 3 \frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{6 + 1}{2} = \frac{7}{2} \] **Step 2: Perform the Operations** Now, substitute the improper fractions back into the expression: \[ \left(\frac{11}{2} + \frac{11}{4}\right) - \frac{7}{2} \] **Step 3: Find a Common Denominator** The common denominator for 2 and 4 is 4. 1. Convert \(\frac{11}{2}\) to fourths: \[ \frac{11}{2} = \frac{11 \times 2}{2 \times 2} = \frac{22}{4} \] 2. \(\frac{11}{4}\) remains the same. 3. Convert \(\frac{7}{2}\) to fourths: \[ \frac{7}{2} = \frac{7 \times 2}{2 \times 2} = \frac{14}{4} \] **Step 4: Perform the Addition and Subtraction** 1. **Addition inside the parentheses:** \[ \frac{22}{4} + \frac{11}{4} = \frac{33}{4} \] 2. **Subtract \(\frac{14}{4}\):** \[ \frac{33}{4} - \frac{14}{4} = \frac{19}{4} \] **Step 5: Convert Back to a Mixed Number (if desired)** \[ \frac{19}{4} = 4 \frac{3}{4} \] **Answer:** \(4 \frac{3}{4}\) --- ### **Problem 2** \[ 10 \] It looks like you've provided the number "10" as Problem 2. Could you please provide more details or specify the problem you'd like assistance with? Whether it's an equation, a word problem, or another type of mathematical question, I'm here to help! --- Feel free to provide additional information or ask further questions!