Factor the following binomial. \[ 8 x^{2}-18 \] \( 2([?] x+\square)(\square x-\square) \)

To factor the binomial \( 8x^2 - 18 \), we can start by factoring out the greatest common factor, which is 2. This gives us: \[ 2(4x^2 - 9) \] Next, we recognize that \( 4x^2 - 9 \) is a difference of squares, which can be factored as: \[ 4x^2 - 9 = (2x)^2 - 3^2 = (2x - 3)(2x + 3) \] Putting it all together, we have: \[ 8x^2 - 18 = 2(2x - 3)(2x + 3) \] Thus, filling in the blanks from your format, we get: \[ 2([2] x+\square)(\square x-\square) \] Here, you can fill in the squares with 3 and -3 respectively, resulting in: \[ 2(2x + 3)(2x - 3) \]