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The value of a truck in 2020 was \( \$ 20,000 \). Its value decreases by \( 1 / 10 \) each year. a. If \( v \) is the value of the truck, in dollars, write an equation for \( v \) (with no commas) in terms of \( n \), the number of years since 2020 . \( v=\square \) b. What is \( v \) when \( n=-2 \) ? Round to the nearest dollar. \( v= \) c. What is \( v \) when \( n=-4 \) ? Round to the nearest dollar. \( v=\square \)

Ask by Pope Dunn. in the United States
Jan 22,2025

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a. \( v = 20000 - 2000n \) b. \( v = 24000 \) c. \( v = 28000 \)

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Mind Expander

To find the value of the truck, we start by noting that it decreases by \( \frac{1}{10} \) each year, meaning it retains \( \frac{9}{10} \) of its value from the previous year. The equation that represents the value of the truck \( v \) in terms of the number of years \( n \) since 2020 is: a. \( v = 20000 \left(\frac{9}{10}\right)^{n} \) Now, let's calculate its values for negative years: b. For \( n = -2 \): \( v = 20000 \left(\frac{9}{10}\right)^{-2} = 20000 \left(\frac{10}{9}\right)^{2} = 20000 \times \frac{100}{81} \approx 2469 \) So, rounded to the nearest dollar, \( v \approx 2469 \). c. For \( n = -4 \): \( v = 20000 \left(\frac{9}{10}\right)^{-4} = 20000 \left(\frac{10}{9}\right)^{4} = 20000 \times \frac{10000}{6561} \approx 3056 \) So, rounded to the nearest dollar, \( v \approx 3056 \).

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