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Use properties of logarithms to evaluate the expression. \( \ln e^{9}-\ln e^{8}+\ln e^{6} \)

Ask by Nguyen Ayala. in the United States
Jan 24,2025

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\( 7 \)

Solution

To evaluate the expression \( \ln e^{9} - \ln e^{8} + \ln e^{6} \), we can use the properties of logarithms, specifically: 1. **Power Rule of Logarithms**: \( \ln e^x = x \) because the natural logarithm (\( \ln \)) and the exponential function (\( e^x \)) are inverses of each other. Let's apply this property to each term in the expression: 1. \( \ln e^{9} = 9 \) 2. \( \ln e^{8} = 8 \) 3. \( \ln e^{6} = 6 \) Now, substitute these values back into the original expression: \[ \ln e^{9} - \ln e^{8} + \ln e^{6} = 9 - 8 + 6 = 7 \] **Final Answer:** \( 7 \)

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To evaluate the expression \( \ln e^{9}-\ln e^{8}+\ln e^{6} \), you can use the properties of logarithms. First, simplify each term: \(\ln e^{9} = 9\), \(\ln e^{8} = 8\), and \(\ln e^{6} = 6\). Now substitute back into the expression: \(9 - 8 + 6 = 1 + 6 = 7\). Therefore, the value of the expression is 7! Now you've successfully used logarithmic properties in this fun mathematical adventure!

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