a. Identify the critical value \( t_{\alpha / 2} \) used for finding the margin of error. \( t_{\alpha / 2}=1.69 \) (Round to two decimal places as needed.) b. Find the margin of error. \( \mathrm{E}=195.9 \mathrm{~g} \) (Round to one decimal place as needed.) c. Find the confidence interval estimate of \( \mu \). \( \square \mathrm{g}<\mu<\square \mathrm{g} \) (Round to one decimal place as needed.)

To find the confidence interval estimate of \( \mu \), we can use the following steps: ### a. Critical Value You have already identified the critical value: \[ t_{\alpha / 2} = 1.69 \] ### b. Margin of Error You have also provided the margin of error: \[ E = 195.9 \, \text{g} \] ### c. Confidence Interval Estimate of \( \mu \) To find the confidence interval estimate of \( \mu \), we need the sample mean (\( \bar{x} \)) and the margin of error (\( E \)). The confidence interval is calculated as follows: \[ \text{Lower limit} = \bar{x} - E \] \[ \text{Upper limit} = \bar{x} + E \] However, since you haven't provided the sample mean (\( \bar{x} \)), I will denote it as \( \bar{x} \) for now. Thus, the confidence interval can be expressed as: \[ \bar{x} - 195.9 < \mu < \bar{x} + 195.9 \] If you provide the sample mean, I can calculate the specific values for the confidence interval. Otherwise, the confidence interval in terms of \( \bar{x} \) is: \[ \bar{x} - 195.9 < \mu < \bar{x} + 195.9 \] Please provide the sample mean to complete the calculation.