Question
- In the figure to the right, I placed an irregular shaped object in a graduated cylinder
that contained 60 mL of water in it. After the irregular shaped object sunk to the bottom,
read the bottom of the meniscus, and the water rose to 90 mL . What is the volume of the
irregular shaped object?
that contained 60 mL of water in it. After the irregular shaped object sunk to the bottom,
read the bottom of the meniscus, and the water rose to 90 mL . What is the volume of the
irregular shaped object?
Ask by Little Colon. in the United States
Jan 21,2025
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Tutor-Verified Answer
Answer
The volume of the irregularly shaped object is 30 mL.
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Beyond the Answer
The volume of the irregular shaped object can be determined by using the water displacement method. Since the water level rose from 60 mL to 90 mL after the object was submerged, you simply subtract the original water level from the new water level: 90 mL - 60 mL = 30 mL. Therefore, the volume of the irregular shaped object is 30 mL.
This method of measuring volume through displacement is based on Archimedes’ principle, which dates back to ancient Greece. Archimedes discovered that when an object is submerged in a fluid, it displaces an amount of fluid equal to its own volume. This principle laid the groundwork for fluid mechanics and remains a fundamental concept in physics today!