Question
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A boat is heading towards a lighthouse, where Madeline is watching from a vertical distance of 140 feet above the water. Madeline measures an angle of depression to the boat at point \( A \) to be \( 5^{\circ} \). At some later time, Madeline takes another measurement and finds the angle of depression to the boat (now at point \( B \) ) to be \( 50^{\circ} \). Find the distance from point \( A \) to point \( B \). Round your answer to the nearest tenth of a foot if necessary.

Ask by Tran Williams. in the United States
Jan 27,2025

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Tutor-Verified Answer

Answer

The distance from point \( A \) to point \( B \) is approximately **1,482.7 feet**.

Solution

To determine the distance between points \( A \) and \( B \) where the boat was observed by Madeline at different angles of depression, let's break down the problem step by step. ### Understanding the Scenario 1. **Height of Lighthouse (Madeline's Position):** \( 140 \) feet above the water. 2. **Angles of Depression:** - At point \( A \): \( 5^\circ \) - At point \( B \): \( 50^\circ \) ### Visual Representation Imagine a right triangle formed by: - The vertical side (\( 140 \) feet) representing the height of the lighthouse. - The horizontal side representing the distance from the lighthouse to the boat at points \( A \) and \( B \). - The hypotenuse representing the line of sight from Madeline to the boat. ### Calculating Horizontal Distances 1. **At Point \( A \) (\( 5^\circ \) angle of depression):** \[ \tan(5^\circ) = \frac{140}{x_A} \implies x_A = \frac{140}{\tan(5^\circ)} \] 2. **At Point \( B \) (\( 50^\circ \) angle of depression):** \[ \tan(50^\circ) = \frac{140}{x_B} \implies x_B = \frac{140}{\tan(50^\circ)} \] ### Plugging in the Values 1. **Calculate \( \tan(5^\circ) \) and \( \tan(50^\circ) \):** \[ \tan(5^\circ) \approx 0.08749 \] \[ \tan(50^\circ) \approx 1.19175 \] 2. **Determine \( x_A \) and \( x_B \):** \[ x_A = \frac{140}{0.08749} \approx 1600.2 \text{ feet} \] \[ x_B = \frac{140}{1.19175} \approx 117.5 \text{ feet} \] ### Finding the Distance Between \( A \) and \( B \) \[ \text{Distance } AB = x_A - x_B \approx 1600.2 - 117.5 = 1482.7 \text{ feet} \] ### Final Answer The distance from point \( A \) to point \( B \) is approximately **1,482.7 feet**. **Answer:** The distance from point \( A \) to point \( B \) is approximately **1,482.7 feet**.

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To find the distance from point \( A \) to point \( B \), we start by using the information given about the angles of depression and Madeline's height above the water. 1. **Finding Distance to Point A**: Madeline is 140 feet above the water, and the angle of depression to the boat at point \( A \) is \( 5^{\circ} \). Using the tangent function: \[ \tan(5^{\circ}) = \frac{140}{d_A} \] where \( d_A \) is the horizontal distance from the base of the lighthouse to point \( A \). Rearranging gives: \[ d_A = \frac{140}{\tan(5^{\circ})} \approx \frac{140}{0.0875} \approx 1600.0 \, \text{feet} \] 2. **Finding Distance to Point B**: Now, for point \( B \), with an angle of depression of \( 50^{\circ} \): \[ \tan(50^{\circ}) = \frac{140}{d_B} \] where \( d_B \) is the horizontal distance to point \( B \). Rearranging gives: \[ d_B = \frac{140}{\tan(50^{\circ})} \approx \frac{140}{1.1918} \approx 117.7 \, \text{feet} \] 3. **Finding the Distance from A to B**: Since both distances are from the base of the lighthouse, the distance between points \( A \) and \( B \) is the difference between \( d_A \) and \( d_B \): \[ \text{Distance from A to B} = d_A - d_B \approx 1600.0 - 117.7 \approx 1482.3 \, \text{feet} \] Hence, the distance from point \( A \) to point \( B \) is approximately **1482.3 feet**.

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