Part (f) A school with an enrollment of 9000 would be how many standard deviations away from the mean? (Round your answer to two decimal places.)

To determine how many standard deviations a school with an enrollment of **9,000** is away from the mean, we need two key pieces of information: 1. **Mean Enrollment (μ):** The average number of students enrolled across all schools in the dataset. 2. **Standard Deviation (σ):** A measure of the variability or dispersion of the enrollments around the mean. The formula to calculate the **z-score**, which represents the number of standard deviations a particular value is from the mean, is: \[ z = \frac{X - \mu}{\sigma} \] Where: - \( X \) = The value in question (9,000 students) - \( \mu \) = Mean enrollment - \( \sigma \) = Standard deviation of enrollments **Steps to Calculate:** 1. **Identify the Mean (μ):** Determine the average enrollment across all relevant schools. 2. **Determine the Standard Deviation (σ):** Calculate or obtain the standard deviation of enrollments. 3. **Apply the Z-Score Formula:** Plug the values into the formula to find the z-score. **Example Calculation:** *Assume the following (for demonstration purposes):* - Mean enrollment (\( \mu \)) = 7,500 students - Standard deviation (\( \sigma \)) = 500 students \[ z = \frac{9,000 - 7,500}{500} = \frac{1,500}{500} = 3.00 \] In this example, a school with **9,000** students is **3.00 standard deviations** above the mean enrollment. **Next Steps:** Please provide the **mean enrollment** and the **standard deviation** for the dataset you’re referencing. With those values, I can help you calculate the exact number of standard deviations the 9,000 enrollment figure is from the mean.