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Find the limits in a), b), and c) below for the function \( f(x)=\frac{4 x}{x-7} \). Use \( -\infty \) and \( \infty \) when appropriate. a) Select the correct choice below and fill in any answer boxes in your choice. A. \( \lim _{x \rightarrow 7^{-}} f(x)=\square \) (Simplify your answer.) B. The limit does not exist and is neither \( -\infty \) nor \( \infty \).

Ask by Mckenzie Todd. in the United States
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

a) \( \lim_{x \rightarrow 7^{-}} f(x) = -\infty \) b) The limit does not exist and is neither \( -\infty \) nor \( \infty \).

Solution

Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 7^{-}}\left(\frac{4x}{x-7}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow 7^{-}}\left(4x\right)}{\lim _{x\rightarrow 7^{-}}\left(x-7\right)}\) - step2: Calculate: \(\frac{28}{\lim _{x\rightarrow 7^{-}}\left(x-7\right)}\) - step3: Calculate: \(-\infty\) Calculate the limit \( \lim_{x \rightarrow 7^{+}} \frac{4x}{x-7} \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 7^{+}}\left(\frac{4x}{x-7}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow 7^{+}}\left(4x\right)}{\lim _{x\rightarrow 7^{+}}\left(x-7\right)}\) - step2: Calculate: \(\frac{28}{\lim _{x\rightarrow 7^{+}}\left(x-7\right)}\) - step3: Calculate: \(+\infty\) To find the limits for the function \( f(x) = \frac{4x}{x-7} \): ### a) 1. **Left-hand limit as \( x \) approaches 7**: - We calculate \( \lim_{x \rightarrow 7^{-}} f(x) \): - As \( x \) approaches 7 from the left, \( x - 7 \) approaches 0 and is negative, making the denominator negative. Therefore, the function approaches \( -\infty \). - Thus, \( \lim_{x \rightarrow 7^{-}} f(x) = -\infty \). 2. **Right-hand limit as \( x \) approaches 7**: - We calculate \( \lim_{x \rightarrow 7^{+}} f(x) \): - As \( x \) approaches 7 from the right, \( x - 7 \) approaches 0 and is positive, making the denominator positive. Therefore, the function approaches \( +\infty \). - Thus, \( \lim_{x \rightarrow 7^{+}} f(x) = +\infty \). ### Conclusion for a) - The correct choice is: - A. \( \lim_{x \rightarrow 7^{-}} f(x) = -\infty \) ### b) - The limit does not exist at \( x = 7 \) because the left-hand limit and right-hand limit are not equal (one approaches \( -\infty \) and the other \( +\infty \)). ### Final Answers: - A. \( \lim_{x \rightarrow 7^{-}} f(x) = -\infty \) - B. The limit does not exist and is neither \( -\infty \) nor \( \infty \).

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Mind Expander

As \( x \) approaches 7 from the left (denoted as \( 7^{-} \)), the function \( f(x)=\frac{4x}{x-7} \) behaves interestingly. The denominator \( x - 7 \) approaches zero but remains negative, while the numerator approaches \( 4 \cdot 7 = 28 \). Thus, you can find: \( \lim _{x \rightarrow 7^{-}} f(x) = \frac{28}{0^{-}} = -\infty. \) Now, let’s jump to the opposite side of 7! When approaching \( 7 \) from the right (denoted as \( 7^{+} \)), the denominator gets closer to zero but is positive. So, you can see: \( \lim _{x \rightarrow 7^{+}} f(x) = \frac{28}{0^{+}} = +\infty. \) So, the limits are negative infinity and positive infinity when coming from the left and right of 7, respectively!

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