Which of the following TWO statements about triangles are true? A. There is no triangle with side lengths of 14 inches, 17 inches, and 32 inches. B. There is exactly 1 triangle with side lengths of 14 inches, 17 inches, and 32 inches. C. There is more than 1 triangle with side lengths of 14 inches, 17 inches, and 32 inches. D. There is no triangle with the angle measures of \( 67^{\circ} \) and \( 100^{\circ} \). E. There is exactly 1 triangle with the angle measures of \( 67^{\circ} \) and \( 100^{\circ} \). F. There is more than 1 triangle with the angle measures of \( 67^{\circ} \) and \( 100^{\circ} \). A triangle has a side length of 13 units and 22 units. Which measurements could be a possible length of the third side? Choose THREE that apply. A. 5 units B. 9.1 units C. 15 units D. 26.5 units E. 35 units F. 44.2 units
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Bonus Knowledge
When it comes to the side lengths of a triangle, they must always adhere to the triangle inequality theorem, which states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 14, 17, and 32 fail this test since 14 + 17 is not greater than 32. That means, statement A is true: there is no triangle with those side lengths. Meanwhile, since the angles of a triangle must sum to \(180^{\circ}\), the given angles \(67^{\circ}\) and \(100^{\circ}\) add up to \(167^{\circ}\), leaving only \(13^{\circ}\) for the third angle. Therefore, statement E is true: there is exactly 1 triangle with these angle measures. For the third side of a triangle with sides of 13 and 22 units, we can again apply the triangle inequality theorem. According to this theorem, the potential third side must be greater than the difference (22 - 13 = 9) and less than the sum (13 + 22 = 35). Therefore, options A (5 units), B (9.1 units), and C (15 units) could potentially work, as they all lie within that range. However, options D (26.5 units) and E (35 units) are ruled out, since 26.5 is valid but exceeds the greatest side sum, and 35 is not valid because it equals the maximum side sum. Option F (44.2 units) also fails nit's way too long!