a) \( 2(x+3)-5(2 x-1)=\frac{1}{5}+10 x \)

Solve the equation \( 2(x+3)-5(2x-1)=\frac{1}{5}+10x \). Solve the equation by following steps: - step0: Solve for \(x\): \(2\left(x+3\right)-5\left(2x-1\right)=\frac{1}{5}+10x\) - step1: Move the expression to the left side: \(2\left(x+3\right)-5\left(2x-1\right)-\left(\frac{1}{5}+10x\right)=0\) - step2: Remove the parentheses: \(2\left(x+3\right)-5\left(2x-1\right)-\frac{1}{5}-10x=0\) - step3: Calculate: \(-18x+\frac{54}{5}=0\) - step4: Move the constant to the right side: \(-18x=0-\frac{54}{5}\) - step5: Remove 0: \(-18x=-\frac{54}{5}\) - step6: Change the signs: \(18x=\frac{54}{5}\) - step7: Multiply by the reciprocal: \(18x\times \frac{1}{18}=\frac{54}{5}\times \frac{1}{18}\) - step8: Multiply: \(x=\frac{3}{5}\) La solución de la ecuación \(2(x+3)-5(2x-1)=\frac{1}{5}+10x\) es \(x=\frac{3}{5}\) o \(x=0.6\).