Question
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4. \( \frac{5 x^{-2} y(3 x y)^{2}}{20 x y} \)

Ask by Simmons Collins. in the Philippines
Jan 24,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ \frac{9\, y^{2}}{4\, x} \]

Solution

To simplify the expression: \[ \frac{5 x^{-2} y (3 x y)^{2}}{20 x y} \] **Step-by-Step Simplification:** 1. **Expand \((3 x y)^2\):** \[ (3 x y)^2 = 3^2 \cdot x^2 \cdot y^2 = 9 x^2 y^2 \] 2. **Substitute back into the original expression:** \[ \frac{5 x^{-2} y \cdot 9 x^2 y^2}{20 x y} = \frac{45 x^{-2} \cdot x^2 \cdot y \cdot y^2}{20 x y} \] 3. **Simplify the \(x\) terms:** \[ x^{-2} \cdot x^2 = x^{(-2 + 2)} = x^0 = 1 \] 4. **Simplify the \(y\) terms:** \[ y \cdot y^2 = y^{1+2} = y^3 \] 5. **Now, the expression becomes:** \[ \frac{45 \cdot y^3}{20 x y} = \frac{45 y^3}{20 x y} \] 6. **Simplify the coefficients and the remaining \(y\) terms:** - Coefficients: \( \frac{45}{20} = \frac{9}{4} \) - \( y^3 / y = y^{3-1} = y^2 \) 7. **Final Simplified Expression:** \[ \frac{9 y^2}{4 x} \] **Answer:** \[ \frac{9\, y^{2}}{4\, x} \]

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Simplify this solution

Beyond the Answer

To simplify the expression, start by expanding it step-by-step. The expression is: \[ \frac{5 x^{-2} y(3 x y)^{2}}{20 x y} \] First, expand the term \( (3xy)^2 \): \[ (3xy)^2 = 9x^2y^2 \] Now substitute this back into the expression: \[ \frac{5 x^{-2} y (9 x^2 y^2)}{20 x y} \] Next, multiply the numerator: \[ 5 x^{-2} y \cdot 9 x^2 y^2 = 45 x^{-2 + 2} y^{1 + 2} = 45 y^3 \] So now we have: \[ \frac{45 y^3}{20 x y} \] Next, simplify: \[ \frac{45 y^3}{20 x y} = \frac{45}{20} \cdot \frac{y^3}{y} \] This reduces to: \[ \frac{45}{20} \cdot y^{3-1} = \frac{45}{20} \cdot y^2 \] Now simplify \(\frac{45}{20}\): \[ \frac{45}{20} = \frac{9}{4} \text{ (dividing both numerator and denominator by 5)} \] Thus, the final simplified expression is: \[ \frac{9 y^2}{4 x} \] So the complete solution is: \[ \frac{9 y^2}{4 x} \]

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