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b. \( \sqrt{(-4)^{2}}+\sqrt{(-1)^{4}} \)

Ask by George Mcfarlane. in Greece
Jan 16,2025

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5

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b. \(\sqrt{(-4)^{2}} + \sqrt{(-1)^{4}}\) Adım adım çözelim: 1. **Karesini Almak:** - \((-4)^{2} = 16\) - \((-1)^{4} = 1\) 2. **Karekökünü Almak:** - \(\sqrt{16} = 4\) - \(\sqrt{1} = 1\) 3. **Toplamak:** - \(4 + 1 = 5\) **Sonuç:** 5

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To solve the expression, let's break it down step-by-step! First, we calculate \((-4)^{2}\), which equals \(16\). The square root of \(16\) is \(4\). Next, we calculate \((-1)^{4}\), which equals \(1\). The square root of \(1\) is \(1\). Now, combine those results: \(4 + 1 = 5\). So, the final answer is \(5\)! For anyone concerned about dealing with square roots involving negative numbers, remember that squaring any negative number will always yield a positive result, making calculations like this straightforward and safe! If you ever encounter a square root of a negative number in your math adventures, you'll be diving into the fascinating world of imaginary numbers!

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