Question

472) An unprepared student makes random guess for ten MCQs questions having 4 options, on a quiz. The probability of atleast one correct answer is: a) 0.9990 b) 0.99 c) 1 d) 0.9437

Ask by Tyler Hanson. in Pakistan
Jan 06,2025

Real Tutor Solution

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Answer

The probability of getting at least one correct answer is approximately 0.9437.

Solution

To determine the probability that an unprepared student gets **at least one** correct answer out of ten multiple-choice questions (MCQs), each with 4 options, we can use the complementary probability approach. ### Step-by-Step Calculation: 1. **Probability of Incorrect Answer for One Question:** - Since there are 4 options and only 1 correct answer, the probability of guessing **incorrectly** is: \[ P(\text{Incorrect}) = \frac{3}{4} = 0.75 \] 2. **Probability of Incorrect Answers for All Ten Questions:** - Since each question is independent, the probability of getting all ten answers incorrect is: \[ P(\text{All Incorrect}) = \left(\frac{3}{4}\right)^{10} \approx 0.0563 \] 3. **Probability of At Least One Correct Answer:** - This is the complement of getting all answers incorrect: \[ P(\text{At Least One Correct}) = 1 - P(\text{All Incorrect}) \approx 1 - 0.0563 = 0.9437 \] ### Conclusion: The probability that the student gets **at least one** correct answer out of ten is approximately **0.9437**. **Answer:** d) 0.9437

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To find the probability of at least one correct answer when a student guesses on 10 multiple-choice questions with 4 options each, we first calculate the probability of getting a question wrong. Since there is 1 correct answer out of 4 options, the probability of guessing wrong is \( \frac{3}{4} \). Therefore, the probability of getting all 10 questions wrong is \( \left( \frac{3}{4} \right)^{10} \). The probability of getting at least one correct answer is then \( 1 - \left( \frac{3}{4} \right)^{10} \), which is approximately 0.9437. So, the answer is (d) 0.9437. Now, understand that probability problems often use the concept of complementary events. Instead of counting the 'success' outcomes directly, sometimes it's easier to calculate how many ways you can fail (in this case, getting all answers wrong) and subtract that from the total certainty (which is 1). This makes it more manageable and often leads to clearer insights!

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