Lin spent \( \frac{5}{6} \) hour on math homework and \( 1 \frac{3}{4} \) hours on science homework. How many hours in all did she spend on homework for both) subjects?
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To find the total time Lin spent on homework for both subjects, we first need to convert the mixed number \( 1 \frac{3}{4} \) hours into an improper fraction. \[ 1 \frac{3}{4} = \frac{4 \cdot 1 + 3}{4} = \frac{4 + 3}{4} = \frac{7}{4} \] Now, we can add \( \frac{5}{6} \) and \( \frac{7}{4} \). To add these fractions, we need a common denominator. The least common multiple of \( 6 \) and \( 4 \) is \( 12 \). Convert both fractions: \[ \frac{5}{6} = \frac{5 \cdot 2}{6 \cdot 2} = \frac{10}{12} \] \[ \frac{7}{4} = \frac{7 \cdot 3}{4 \cdot 3} = \frac{21}{12} \] Now we can add: \[ \frac{10}{12} + \frac{21}{12} = \frac{10 + 21}{12} = \frac{31}{12} \] Converting this improper fraction back into a mixed number: \[ \frac{31}{12} = 2 \frac{7}{12} \] Thus, Lin spent a total of \( 2 \frac{7}{12} \) hours on homework for both subjects.