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Lin spent \( \frac{5}{6} \) hour on math homework and \( 1 \frac{3}{4} \) hours on science homework. How many hours in all did she spend on homework for both) subjects?

Ask by Ward Knight. in the United States
Jan 22,2025

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Answer

Lin spent a total of \( 2 \frac{7}{12} \) hours on homework for both math and science.

Solution

To find the total time Lin spent on both math and science homework, we'll add the time spent on each subject together. Here's a step-by-step breakdown: 1. **Convert Mixed Numbers to Improper Fractions (if necessary):** - **Math Homework:** \( \frac{5}{6} \) hour (already a simple fraction). - **Science Homework:** \( 1 \frac{3}{4} \) hours. Convert \( 1 \frac{3}{4} \) to an improper fraction: \[ 1 \frac{3}{4} = \frac{4 \times 1 + 3}{4} = \frac{7}{4} \] 2. **Add the Two Fractions:** \[ \frac{5}{6} + \frac{7}{4} \] To add these fractions, they need a common denominator. The least common denominator (LCD) for 6 and 4 is 12. 3. **Convert Each Fraction to Have the Common Denominator:** - **Math Homework:** \[ \frac{5}{6} = \frac{5 \times 2}{6 \times 2} = \frac{10}{12} \] - **Science Homework:** \[ \frac{7}{4} = \frac{7 \times 3}{4 \times 3} = \frac{21}{12} \] 4. **Add the Converted Fractions:** \[ \frac{10}{12} + \frac{21}{12} = \frac{31}{12} \] This improper fraction can be converted back to a mixed number: \[ \frac{31}{12} = 2 \frac{7}{12} \] 5. **Conclusion:** Lin spent a total of \( 2 \frac{7}{12} \) hours on homework for both math and science. **Answer:** Lin spent a total of \( 2 \frac{7}{12} \) hours on homework for both subjects.

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To find the total time Lin spent on homework for both subjects, we first need to convert the mixed number \( 1 \frac{3}{4} \) hours into an improper fraction. \[ 1 \frac{3}{4} = \frac{4 \cdot 1 + 3}{4} = \frac{4 + 3}{4} = \frac{7}{4} \] Now, we can add \( \frac{5}{6} \) and \( \frac{7}{4} \). To add these fractions, we need a common denominator. The least common multiple of \( 6 \) and \( 4 \) is \( 12 \). Convert both fractions: \[ \frac{5}{6} = \frac{5 \cdot 2}{6 \cdot 2} = \frac{10}{12} \] \[ \frac{7}{4} = \frac{7 \cdot 3}{4 \cdot 3} = \frac{21}{12} \] Now we can add: \[ \frac{10}{12} + \frac{21}{12} = \frac{10 + 21}{12} = \frac{31}{12} \] Converting this improper fraction back into a mixed number: \[ \frac{31}{12} = 2 \frac{7}{12} \] Thus, Lin spent a total of \( 2 \frac{7}{12} \) hours on homework for both subjects.

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