Question
upstudy study bank question image url

Given the function \( f(x)=\int_{1}^{x}\left(t^{4}-12 t^{3}-28 t^{2}\right) d t \), determine all \( x- \) values, if any, for which \( f \) has a relative minimum.

Ask by Carroll Washington. in the United States
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The function \( f(x) \) has a relative minimum at \( x = 14 \).

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Reviewed and approved by the UpStudy tutoring team

The Deep Dive

To determine the `x`-values for which the function \( f(x) \) has a relative minimum, you first need to find the derivative of the function. According to the Fundamental Theorem of Calculus, the derivative is given by: \[ f'(x) = t^{4} - 12 t^{3} - 28 t^{2} \bigg|_{t=x} = x^{4} - 12 x^{3} - 28 x^{2} \] Next, set the derivative equal to zero to find critical points: \[ x^{4} - 12 x^{3} - 28 x^{2} = 0 \] Factor out \( x^{2} \): \[ x^{2}(x^{2} - 12 x - 28) = 0 \] From here, \( x^{2} = 0 \) gives \( x = 0 \), and for \( x^{2} - 12 x - 28 = 0 \), you can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{12 \pm \sqrt{144 + 112}}{2} = \frac{12 \pm \sqrt{256}}{2} = \frac{12 \pm 16}{2} \] This results in: 1. \( x = 14 \) 2. \( x = -2 \) Now, to determine if these points are relative minima, you can use the second derivative test. Calculate \( f''(x) \): \[ f''(x) = 4x^{3} - 36x^{2} - 56x \] Evaluate \( f''(x) \) at the critical points: 1. At \( x = 0 \): \[ f''(0) = 4(0)^{3} - 36(0)^{2} - 56(0) = 0 \quad (\text{Inconclusive}) \] 2. At \( x = 14 \): \[ f''(14) = 4(14)^{3} - 36(14)^{2} - 56(14) \] Calculate term by term, and if \( f''(14) > 0 \), \( x = 14 \) is a local minimum. 3. At \( x = -2 \): \[ f''(-2) = 4(-2)^{3} - 36(-2)^{2} - 56(-2) \] Confirm \( f''(-2) < 0 \) shows \( x = -2 \) is a local maximum. Thus, the only critical point \( x = 14 \) would be where \( f(x) \) has a relative minimum. ### Conclusion: Therefore, the \( x \)-value for which \( f \) has a relative minimum is \( x = 14 \). --- History shows that calculus was formalized in the late 17th century by Isaac Newton and Gottfried Wilhelm Leibniz, who independently developed the concepts of differentiation and integration. Their principles laid the groundwork for understanding how functions behave and change over time, forming the backbone of classical mechanics. In the real world, finding relative minima is crucial in fields like economics for cost minimization, engineering for optimizing material usage, or even in machine learning for minimizing the error of predictive models. Understanding these points helps in making strategic decisions based on data analysis and optimization.

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy