4. \( 2 \frac{3}{5}-1 \frac{3}{8} \)
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To solve \( 2 \frac{3}{5}-1 \frac{3}{8} \), first convert the mixed numbers to improper fractions. For \( 2 \frac{3}{5} \), it becomes \( \frac{2 \times 5 + 3}{5} = \frac{10 + 3}{5} = \frac{13}{5} \). For \( 1 \frac{3}{8} \), it converts to \( \frac{1 \times 8 + 3}{8} = \frac{8 + 3}{8} = \frac{11}{8} \). Now, perform the subtraction: \( \frac{13}{5} - \frac{11}{8} \). To subtract these, find a common denominator, which is 40. So, convert the fractions: \( \frac{13}{5} = \frac{13 \times 8}{5 \times 8} = \frac{104}{40} \) and \( \frac{11}{8} = \frac{11 \times 5}{8 \times 5} = \frac{55}{40} \). Now subtract: \( \frac{104}{40} - \frac{55}{40} = \frac{49}{40} \). Finally, convert \( \frac{49}{40} \) back to a mixed number: \( 1 \frac{9}{40} \). So, \( 2 \frac{3}{5} - 1 \frac{3}{8} = 1 \frac{9}{40} \).