$$ \operatorname{Sen} 30^{\circ}=\frac{\frac{1}{2}}{1} \Leftrightarrow \operatorname{Sen} 30^{\circ}=\frac{1}{2} $$ e $$ \operatorname{Cos} 30^{\circ}=\frac{h}{1} $$

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Dadas as seguintes equações trigonométricas:

$$
\operatorname{Sen} 30^{\circ} = \frac{\frac{1}{2}}{1} \quad \Leftrightarrow \quad \operatorname{Sen} 30^{\circ} = \frac{1}{2}
$$

$$
\operatorname{Cos} 30^{\circ} = \frac{h}{1}
$$

Sabemos que:

- $$\operatorname{Sen} 30^{\circ} = \frac{1}{2}$$
- $$\operatorname{Cos} 30^{\circ} = \frac{\sqrt{3}}{2}$$

A segunda equação pode ser resolvida para $$h$$:

$$
\operatorname{Cos} 30^{\circ} = \frac{h}{1} \quad \Rightarrow \quad h = \operatorname{Cos} 30^{\circ} = \frac{\sqrt{3}}{2}
$$

Portanto, o valor de $$h$$ é:

$$
h = \frac{\sqrt{3}}{2}
$$
$$ h = \frac{\sqrt{3}}{2} $$

e

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