Calculate the percentage of both elements in sulfur dioxide. Calculate the percentage composition of ammonium nitrate, $$ \mathrm{NH}_{4} \mathrm{NO}_{ ext {O }} $$

Question

Calculate the percentage of both elements in sulfur dioxide. Calculate the percentage composition of ammonium nitrate, $$ \mathrm{NH}_{4} \mathrm{NO}_{	ext {O }} $$

UpStudy AI · Accepted Answer

Sure, I'd be happy to help you calculate the percentage composition of both sulfur dioxide (SO₂) and ammonium nitrate (NH₄NO₃). Percentage composition determines the percentage by mass of each element in a compound.

---

## 1. **Percentage Composition of Sulfur Dioxide (SO₂)**

**Step 1: Determine the molar masses of each element.**

- **Sulfur (S):** Approximately 32.07 g/mol
- **Oxygen (O):** Approximately 16.00 g/mol

**Step 2: Calculate the total molar mass of SO₂.**

$$
\text{Molar mass of SO}_2 = (\text{1 S} \times 32.07\, \text{g/mol}) + (\text{2 O} \times 16.00\, \text{g/mol}) = 32.07 + 32.00 = 64.07\, \text{g/mol}
$$

**Step 3: Calculate the percentage of each element.**

- **Percentage of Sulfur (S):**

$$
\left( \frac{32.07\, \text{g/mol}}{64.07\, \text{g/mol}} \right) \times 100\% \approx 50.05\%
$$

- **Percentage of Oxygen (O):**

$$
\left( \frac{32.00\, \text{g/mol}}{64.07\, \text{g/mol}} \right) \times 100\% \approx 49.95\%
$$

**Summary for SO₂:**
- **Sulfur (S):** ~50.05%
- **Oxygen (O):** ~49.95%

---

## 2. **Percentage Composition of Ammonium Nitrate (NH₄NO₃)**

Ammonium nitrate has the chemical formula NH₄NO₃, which can also be viewed as NH₄⁺ (ammonium ion) and NO₃⁻ (nitrate ion).

**Step 1: Determine the molar masses of each element.**

- **Nitrogen (N):** Approximately 14.01 g/mol
- **Hydrogen (H):** Approximately 1.008 g/mol
- **Oxygen (O):** Approximately 16.00 g/mol

**Step 2: Calculate the total molar mass of NH₄NO₃.**

$$
\text{Molar mass of NH}_4\text{NO}_3 = (\text{2 N} \times 14.01\, \text{g/mol}) + (\text{4 H} \times 1.008\, \text{g/mol}) + (\text{3 O} \times 16.00\, \text{g/mol}) 
$$
$$
= 28.02 + 4.032 + 48.00 = 80.052\, \text{g/mol}
$$

**Step 3: Calculate the percentage of each element.**

- **Percentage of Nitrogen (N):**

$$
\left( \frac{28.02\, \text{g/mol}}{80.05\, \text{g/mol}} \right) \times 100\% \approx 35.00\%
$$

- **Percentage of Hydrogen (H):**

$$
\left( \frac{4.032\, \text{g/mol}}{80.05\, \text{g/mol}} \right) \times 100\% \approx 5.04\%
$$

- **Percentage of Oxygen (O):**

$$
\left( \frac{48.00\, \text{g/mol}}{80.05\, \text{g/mol}} \right) \times 100\% \approx 59.96\%
$$

**Summary for NH₄NO₃:**
- **Nitrogen (N):** ~35.00%
- **Hydrogen (H):** ~5.04%
- **Oxygen (O):** ~59.96%

---

### **Final Summary**

1. **Sulfur Dioxide (SO₂):**
   - Sulfur (S): ~50.05%
   - Oxygen (O): ~49.95%

2. **Ammonium Nitrate (NH₄NO₃):**
   - Nitrogen (N): ~35.00%
   - Hydrogen (H): ~5.04%
   - Oxygen (O): ~59.96%

*Note: Due to rounding during calculations, the total percentages may not add up to exactly 100%.*
- **Sulfur Dioxide (SO₂):** - Sulfur (S): ~50.05% - Oxygen (O): ~49.95% - **Ammonium Nitrate (NH₄NO₃):** - Nitrogen (N): ~35.00% - Hydrogen (H): ~5.04% - Oxygen (O): ~59.96%

Calculate the percentage of both elements in sulfur dioxide. Calculate the percentage composition of ammonium nitrate, \( \mathrm{NH}_{4} \mathrm{NO}_{\text {O }} \)

Real Tutor Solution

Answer

Solution

Beyond the Answer

Related Questions

Latest Chemistry Questions