Question
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23. Spatis When Alonzo, who is \( 5^{\prime} 11^{\prime \prime} \) tall, stands next to a basketball goal, his shadow is \( 2^{\prime} \) 'ong, and the basketball goal's shadow is \( 4^{\prime} 4^{\prime \prime} \) long. About how tall is the basketbail goal?

Ask by Weston Rodriguez. in the United States
Dec 29,2024

Real Tutor Solution

Tutor-Verified Answer

Answer

The basketball goal is about 12 feet 10 inches tall.

Solution

To solve the problem, we can use the concept of similar triangles. The height of Alonzo and the length of his shadow form one triangle, while the height of the basketball goal and the length of its shadow form another triangle. ### Known Conditions: 1. Alonzo's height: \( 5' 11'' \) 2. Alonzo's shadow length: \( 2' \) 3. Basketball goal's shadow length: \( 4' 4'' \) ### Step 1: Convert heights and lengths to a single unit (inches) - Alonzo's height in inches: \[ 5' 11'' = 5 \times 12 + 11 = 60 + 11 = 71 \text{ inches} \] - Alonzo's shadow length in inches: \[ 2' = 2 \times 12 = 24 \text{ inches} \] - Basketball goal's shadow length in inches: \[ 4' 4'' = 4 \times 12 + 4 = 48 + 4 = 52 \text{ inches} \] ### Step 2: Set up the proportion using similar triangles Let \( h \) be the height of the basketball goal in inches. The proportion based on similar triangles is: \[ \frac{\text{Height of Alonzo}}{\text{Length of Alonzo's shadow}} = \frac{\text{Height of basketball goal}}{\text{Length of basketball goal's shadow}} \] This can be written as: \[ \frac{71}{24} = \frac{h}{52} \] ### Step 3: Solve for \( h \) Cross-multiplying gives: \[ 71 \times 52 = 24 \times h \] Calculating \( 71 \times 52 \): \[ 71 \times 52 = 3692 \] So we have: \[ 3692 = 24h \] Now, divide both sides by 24 to find \( h \): \[ h = \frac{3692}{24} \] ### Step 4: Calculate \( h \) Now, let's perform the division: \[ h = 153.8333 \text{ inches} \] ### Step 5: Convert \( h \) back to feet and inches To convert inches back to feet and inches: - Feet: \( \lfloor \frac{153.8333}{12} \rfloor = 12 \) feet - Remaining inches: \( 153.8333 - (12 \times 12) = 153.8333 - 144 = 9.8333 \) inches Thus, the height of the basketball goal is approximately \( 12' 10'' \). ### Final Answer: The basketball goal is about \( 12' 10'' \) tall.

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Bonus Knowledge

To find the height of the basketball goal using similar triangles, we can set up a proportion based on the lengths of Alonzo's height and shadow compared to the basketball goal's height and shadow. We know that Alonzo's height is \( 5^{\prime} 11^{\prime \prime} \) (which converts to 71 inches) and his shadow is \( 2^{\prime} \) long (or 24 inches). The basketball goal's shadow is \( 4^{\prime} 4^{\prime \prime} \) (which converts to 52 inches). Using the proportion: \[ \frac{\text{Height of Alonzo}}{\text{Shadow of Alonzo}} = \frac{\text{Height of Goal}}{\text{Shadow of Goal}} \] \[ \frac{71}{24} = \frac{\text{Height of Goal}}{52} \] Cross-multiplying gives: \[ 71 \times 52 = 24 \times \text{Height of Goal} \] \[ 3692 = 24 \times \text{Height of Goal} \] \[ \text{Height of Goal} = \frac{3692}{24} \approx 153.83 \text{ inches} \] Thus, the height of the basketball goal is approximately 154 inches, or about 12 feet 10 inches!

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