Question
Question 1 of 18, Step 1 of 1 Growing linearly, the balance owed on your credit card doubles from \( \$ 800 \) to \( \$ 1600 \) in 6 months. If the balance were growing according to the exponential function \( f(x)=800(1+0.122)^{x} \) where \( x \) represents the number of months, what would the balance be after 6 months? Round your answer to the nearest cent. Answer How to enter your answer (opens in new window) Keyboard Shortrus Kist
Ask by Wagner Reeves. in the United States
Jan 22,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
After 6 months, the balance would be \$1,596.08.
Solution
To determine the balance after 6 months using the exponential growth model \( f(x) = 800(1 + 0.122)^x \), where \( x \) represents the number of months, follow these steps:
### Step 1: Identify the Given Information
- **Initial Balance (\( f(0) \))**: \$800
- **Growth Rate per Month**: 12.2% (or 0.122 in decimal form)
- **Time (\( x \))**: 6 months
### Step 2: Apply the Exponential Growth Formula
The exponential growth formula is:
\[
f(x) = 800(1 + 0.122)^x
\]
Plugging in \( x = 6 \):
\[
f(6) = 800(1 + 0.122)^6 = 800(1.122)^6
\]
### Step 3: Calculate \( (1.122)^6 \)
Let's compute \( (1.122)^6 \):
1. **First Month:**
\[
1.122^1 = 1.122
\]
2. **Second Month:**
\[
1.122^2 = 1.122 \times 1.122 \approx 1.258884
\]
3. **Third Month:**
\[
1.122^3 = 1.258884 \times 1.122 \approx 1.412477
\]
4. **Fourth Month:**
\[
1.122^4 = 1.412477 \times 1.122 \approx 1.5848
\]
5. **Fifth Month:**
\[
1.122^5 = 1.5848 \times 1.122 \approx 1.7781
\]
6. **Sixth Month:**
\[
1.122^6 = 1.7781 \times 1.122 \approx 1.9951
\]
So,
\[
(1.122)^6 \approx 1.9951
\]
### Step 4: Calculate the Final Balance
Multiply the result by the initial balance:
\[
f(6) = 800 \times 1.9951 \approx 1596.08
\]
### Step 5: Round to the Nearest Cent
\[
f(6) \approx \$1596.08
\]
### **Answer**
After 6 months, the balance would be **\$1,596.08**.
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Extra Insights
To find the balance owed on your credit card after 6 months using the exponential function \( f(x) = 800(1 + 0.122)^x \), just plug in \( x = 6 \): \[ f(6) = 800(1 + 0.122)^6 \] Calculating, we get: \[ f(6) = 800(1.122)^6 \approx 800(1.888) \approx 1510.60 \] So after 6 months, the balance would be approximately \$1510.60. And don't forget, by choosing this model, you're reflecting a kind of growth that compounds over time, which mirrors how many debts pile up quicker than we expect!