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Question 15 Find the domain of \( f(x)=\sqrt{x-2} \) Use two lower case o's for infinity. "oo" is how you type in infinity. Question Help: Video \( \square \) Message instructor Submit Question Question 16
Ask by Garrett French. in the United States
Jan 23,2025
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Answer
The domain of \( f(x) = \sqrt{x - 2} \) is all real numbers \( x \) such that \( x \geq 2 \), which is written as \( [2, \infty) \).
Solution
To find the domain of the function \( f(x) = \sqrt{x - 2} \), we need to determine the values of \( x \) for which the expression under the square root is non-negative, since the square root of a negative number is not defined in the set of real numbers.
### Step 1: Set the expression under the square root greater than or equal to zero.
\[
x - 2 \geq 0
\]
### Step 2: Solve the inequality.
To solve for \( x \), we can add 2 to both sides:
\[
x \geq 2
\]
### Step 3: Write the domain in interval notation.
The solution indicates that \( x \) can take any value greater than or equal to 2. In interval notation, this is expressed as:
\[
[2, oo)
\]
### Conclusion
The domain of the function \( f(x) = \sqrt{x - 2} \) is \( [2, oo) \).
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To determine the domain of \( f(x) = \sqrt{x-2} \), the expression under the square root must be non-negative. This means we need \( x - 2 \geq 0 \), resulting in \( x \geq 2 \). Therefore, the domain of the function is \( [2, oo) \). In the world of math, square roots can only handle non-negative numbers! So, if you ever find yourself with a square root of a negative number, it's like trying to fit a square peg in a round hole—trust me, it's just not going to work. Stick to the positives for smooth sailing!