Question
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Use the imaginary number \( i \) to rewrite the expression below as a complex number. Sim all radicals. \( 8-\sqrt{-34} \) \begin{tabular}{|l|l}\hline \\ \hline\end{tabular}

Ask by Frank Best. in the United States
Jan 24,2025

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Answer

\( 8 - i\sqrt{34} \)

Solution

To rewrite the expression \( 8 - \sqrt{-34} \) as a complex number using the imaginary unit \( i \), follow these steps: 1. **Identify the Imaginary Part:** - The square root of a negative number introduces the imaginary unit \( i \), where \( i = \sqrt{-1} \). - Therefore, \( \sqrt{-34} = \sqrt{34} \cdot \sqrt{-1} = \sqrt{34} \, i \). 2. **Rewrite the Expression:** - Substitute \( \sqrt{-34} \) with \( \sqrt{34} \, i \) in the original expression: \[ 8 - \sqrt{-34} = 8 - \sqrt{34} \, i \] 3. **Express as a Complex Number:** - A complex number is typically written in the form \( a + b i \), where \( a \) is the real part and \( b i \) is the imaginary part. - In this case, the complex number is: \[ 8 - i\sqrt{34} \] **Final Answer:** \[ 8 - i\,\sqrt{34} \]

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To rewrite the expression \( 8 - \sqrt{-34} \) as a complex number, we start by recognizing that \( \sqrt{-34} \) can be expressed using the imaginary unit \( i \). This gives us: \[ \sqrt{-34} = \sqrt{34} \cdot i \] Substituting this back into the original expression, we get: \[ 8 - \sqrt{-34} = 8 - \sqrt{34} \cdot i \] Thus, the expression as a complex number is: \[ 8 - \sqrt{34} \cdot i \] This means the real part is \( 8 \) and the imaginary part is \( -\sqrt{34} \).

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