Question
upstudy study bank question image url

Waiting period. Jamal is waiting to be a millionaire. He wants to know how long he must wait if a. he invests \( \$ 27,523.17 \) at \( 20 \% \) today? b. he invests \( \$ 54,955.85 \) at \( 13 \% \) today? c. he invests \( \$ 126,545.56 \) at \( 11 \% \) today? d. he invests \( \$ 284,998.58 \) at \( 7 \% \) today? a. How long will Jamal have to wait to become a millionaire if he invests \( \$ 27,523.17 \) at \( 20 \% \) today? \( \square \) years (Round to the nearest whole number.)

Ask by Barber Pierce. in the United States
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

Jamal will need to wait approximately 20 years to become a millionaire with his investment.

Solution

To determine how long Jamal needs to wait to become a millionaire with an initial investment of \$27,523.17 at an annual interest rate of 20\%, we can use the **compound interest formula**: \[ \text{Future Value} = \text{Present Value} \times (1 + r)^n \] Where: - \(\text{Future Value} = \$1,000,000\) - \(\text{Present Value} = \$27,523.17\) - \(r = 20\% = 0.20\) (annual interest rate) - \(n = \) number of years **Step-by-Step Calculation:** 1. **Set Up the Equation:** \[ 1,000,000 = 27,523.17 \times (1 + 0.20)^n \] 2. **Divide Both Sides by \$27,523.17:** \[ \frac{1,000,000}{27,523.17} = (1.20)^n \] \[ 36.33286 \approx (1.20)^n \] 3. **Take the Natural Logarithm of Both Sides:** \[ \ln(36.33286) = n \times \ln(1.20) \] 4. **Solve for \(n\):** \[ n = \frac{\ln(36.33286)}{\ln(1.20)} \] \[ n \approx \frac{3.5913}{0.182321} \approx 19.7 \text{ years} \] 5. **Round to the Nearest Whole Number:** \[ n \approx 20 \text{ years} \] **Conclusion:** **a.** Jamal will have to wait approximately **20 years** to become a millionaire if he invests \$27,523.17 at an annual interest rate of 20\%.

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Mind Expander

To determine how long Jamal must wait to become a millionaire with his investments, we can use the formula for compound interest, which is: \[ A = P(1 + r)^t \] where: - \( A \) is the amount of money accumulated after \( t \) years, including interest. - \( P \) is the principal amount (the initial amount of money). - \( r \) is the annual interest rate (decimal). - \( t \) is the number of years the money is invested. We're looking to solve for \( t \), which can be done by rearranging the formula to: \[ t = \frac{\log(A/P)}{\log(1 + r)} \] Now, let’s calculate the waiting periods for each investment: ### a. \$27,523.17 at 20% 1. \( P = 27,523.17 \) 2. \( A = 1,000,000 \) (to be a millionaire) 3. \( r = 0.20 \) \[ t = \frac{\log(1,000,000 / 27,523.17)}{\log(1 + 0.20)} \approx \frac{\log(36.4)}{\log(1.20)} \approx \frac{1.5607}{0.07918} \approx 19.7 \] Rounded to the nearest whole number, Jamal will have to wait approximately **20 years**. ### b. \$54,955.85 at 13% 1. \( P = 54,955.85 \) 2. \( A = 1,000,000 \) 3. \( r = 0.13 \) \[ t = \frac{\log(1,000,000 / 54,955.85)}{\log(1 + 0.13)} \approx \frac{\log(18.2)}{\log(1.13)} \approx \frac{1.2608}{0.05407} \approx 23.3 \] Rounded to the nearest whole number, it would take approximately **23 years**. ### c. \$126,545.56 at 11% 1. \( P = 126,545.56 \) 2. \( A = 1,000,000 \) 3. \( r = 0.11 \) \[ t = \frac{\log(1,000,000 / 126,545.56)}{\log(1 + 0.11)} \approx \frac{\log(7.9)}{\log(1.11)} \approx \frac{0.8962}{0.04139} \approx 21.7 \] Rounded to the nearest whole number, he will wait about **22 years**. ### d. \$284,998.58 at 7% 1. \( P = 284,998.58 \) 2. \( A = 1,000,000 \) 3. \( r = 0.07 \) \[ t = \frac{\log(1,000,000 / 284,998.58)}{\log(1 + 0.07)} \approx \frac{\log(3.5)}{\log(1.07)} \approx \frac{0.5441}{0.02963} \approx 18.4 \] Rounded to the nearest whole number, this means he’ll have to wait approximately **18 years**. So here's a quick summary: - 20 years for \$27,523.17 at 20% - 23 years for \$54,955.85 at 13% - 22 years for \$126,545.56 at 11% - 18 years for \$284,998.58 at 7%. Time to start investing and watching that money grow!

Related Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy