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7. Solve the equation \( \sqrt[3]{-2 x+5}=-3 \) for \( x \)

Ask by Mcguire Mann. in the United States
Jan 23,2025

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Tutor-Verified Answer

Answer

\( x = 16 \)

Solution

To solve the equation \( \sqrt[3]{-2x + 5} = -3 \) for \( x \), follow these steps: 1. **Eliminate the Cube Root:** To remove the cube root, cube both sides of the equation: \[ \left( \sqrt[3]{-2x + 5} \right)^3 = (-3)^3 \] Simplifying both sides: \[ -2x + 5 = -27 \] 2. **Isolate the Term with \( x \):** Subtract 5 from both sides to isolate the term containing \( x \): \[ -2x + 5 - 5 = -27 - 5 \] Simplifying: \[ -2x = -32 \] 3. **Solve for \( x \):** Divide both sides by -2 to solve for \( x \): \[ \frac{-2x}{-2} = \frac{-32}{-2} \] Simplifying: \[ x = 16 \] **Solution:** \[ x = 16 \]

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To solve the equation \( \sqrt[3]{-2 x+5}=-3 \), start by cubing both sides to eliminate the cube root. This gives you: \[ -2x + 5 = (-3)^3 \] Calculating the right side yields: \[ -2x + 5 = -27 \] Next, isolate \( -2x \) by subtracting 5 from both sides: \[ -2x = -27 - 5 \] This simplifies to: \[ -2x = -32 \] Now, divide both sides by -2 to solve for \( x \): \[ x = \frac{-32}{-2} = 16 \] Thus, the solution to the equation is \( x = 16 \).

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