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Evaluate the piecewise function at the given values of the independent variable. \( f(x)=\left\{\begin{array}{ll}5 x+4 & \text { if } x<0 \\ 2 x+5 & \text { if } x \geq 0\end{array}\right. \) (a) \( f(-1) \) (b) \( f(0) \) (c) \( f(2) \)

Ask by Elliott Brewer. in the United States
Jan 25,2025

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Tutor-Verified Answer

Answer

\( f(-1) = -1 \), \( f(0) = 5 \), \( f(2) = 9 \).

Solution

Let's evaluate the piecewise function \( f(x) \) at the specified values of \( x \): \[ f(x) = \begin{cases} 5x + 4 & \text{if } x < 0 \\ 2x + 5 & \text{if } x \geq 0 \end{cases} \] ### (a) \( f(-1) \) **Step 1:** Determine which part of the piecewise function to use. Since \( -1 < 0 \), we use: \[ f(x) = 5x + 4 \] **Step 2:** Substitute \( x = -1 \) into the function. \[ f(-1) = 5(-1) + 4 = -5 + 4 = -1 \] **Answer:** \( f(-1) = -1 \) --- ### (b) \( f(0) \) **Step 1:** Determine which part of the piecewise function to use. Since \( 0 \geq 0 \), we use: \[ f(x) = 2x + 5 \] **Step 2:** Substitute \( x = 0 \) into the function. \[ f(0) = 2(0) + 5 = 0 + 5 = 5 \] **Answer:** \( f(0) = 5 \) --- ### (c) \( f(2) \) **Step 1:** Determine which part of the piecewise function to use. Since \( 2 \geq 0 \), we use: \[ f(x) = 2x + 5 \] **Step 2:** Substitute \( x = 2 \) into the function. \[ f(2) = 2(2) + 5 = 4 + 5 = 9 \] **Answer:** \( f(2) = 9 \) --- **Summary of Results:** - **(a)** \( f(-1) = -1 \) - **(b)** \( f(0) = 5 \) - **(c)** \( f(2) = 9 \)

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The Deep Dive

Let's evaluate the piecewise function \( f(x) \) at the given values. (a) For \( f(-1) \): Since \(-1 < 0\), we use the first part of the function: \[ f(-1) = 5(-1) + 4 = -5 + 4 = -1. \] (b) For \( f(0) \): Since \(0 \geq 0\), we use the second part of the function: \[ f(0) = 2(0) + 5 = 0 + 5 = 5. \] (c) For \( f(2) \): Since \(2 \geq 0\), we use the second part of the function: \[ f(2) = 2(2) + 5 = 4 + 5 = 9. \] So the evaluations are: (a) \( f(-1) = -1 \) (b) \( f(0) = 5 \) (c) \( f(2) = 9 \)

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