\begin{tabular}{l|l}\( \begin{array}{l}\text { Solve these simultaneous } \\ \text { equations using a graphical }\end{array} \) & Tip \\ method. & \( \begin{array}{l}\text { Rearrange both equations to make } y \text { the subject } \\ \text { then draw tables of values for } x=0,2 \text { and } 4 . \\ 3 x+y=8\end{array} \) \\ \hline\end{tabular}

To solve the equation \(3x + y = 8\) for \(y\), we rearrange it to get \(y = 8 - 3x\). Now, by substituting \(x\) values of 0, 2, and 4, we can find the corresponding \(y\) values: - For \(x = 0\), \(y = 8 - 3(0) = 8\) - For \(x = 2\), \(y = 8 - 3(2) = 2\) - For \(x = 4\), \(y = 8 - 3(4) = -4\) Plot these points \((0,8)\), \((2,2)\), and \((4,-4)\) on a graph and connect them to visualize the line. Now, once you have one equation in graphical form, try the same process for a second equation. This allows you to identify the point of intersection where both lines meet; that point will be your solution to the simultaneous equations.