Simplify \( 3 \sqrt{450}-\sqrt{32} \) \( [?] \sqrt{[\square}] \)
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To simplify \( 3 \sqrt{450} - \sqrt{32} \), let's break it down. First, simplify \( \sqrt{450} \): \( \sqrt{450} = \sqrt{225 \times 2} = \sqrt{225} \cdot \sqrt{2} = 15\sqrt{2} \). Therefore, \( 3 \sqrt{450} = 3 \cdot 15\sqrt{2} = 45\sqrt{2} \). Next, simplify \( \sqrt{32} \): \( \sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \cdot \sqrt{2} = 4\sqrt{2} \). Now, combine the simplified terms: \[ 45\sqrt{2} - 4\sqrt{2} = (45 - 4)\sqrt{2} = 41\sqrt{2} \] So, the simplified expression is \[ 41\sqrt{2} \] Thus, the answer is \( [41] \sqrt{[2]} \).