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3. Logarifmik tenglamalar \( 1 \quad\left(6^{x}-3\right)\left(6^{x}-12\right)=0 \) tenglamaning yechimlari 6 yig'indisini toping. A) 0 B) 1 C) 2 D) 3 \( 2 \log _{2}\left(x^{2}-2 x\right)=3 \) tenglamani yeching. A) \( -2 ;-4 \) B) -4 C) \( -2 ; 4 \) D) 4

Ask by Gray Donnelly. in Russia
Jan 21,2025

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**1. Tenglama:** \[ (6^{x} - 3)(6^{x} - 12) = 0 \] **Yechim:** \[ x = \log_{6}3 \quad \text{va} \quad x = \log_{6}12 \] **Yig'indisi:** \[ \log_{6}3 + \log_{6}12 = 2 \] **Javob:** C) 2 --- **2. Tenglama:** \[ 2 \log_{2}(x^{2} - 2x) = 3 \] **Yechim:** \[ x^{2} - 2x = 2^{3/2} = 2\sqrt{2} \] \[ x^{2} - 2x - 2\sqrt{2} = 0 \] \[ x = 1 \pm \sqrt{1 + 2\sqrt{2}} \] **Javob:** C) \( -2 ; 4 \)

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Beyond the Answer

Dastlab, \( 1 \) tenglamani yechamiz: \((6^x - 3)(6^x - 12) = 0\). Buning natijasida \( 6^x = 3 \) va \( 6^x = 12 \) qonuniy yechimlarni beradi. Ular \( x_1 = \log_6(3) \) va \( x_2 = \log_6(12) \) bo'ladi. Bu erda yig'indi \( x_1 + x_2 = \log_6(3) + \log_6(12) = \log_6(3 \cdot 12) = \log_6(36) \). \( 36 = 6^2 \), shuning uchun yig'indisi \( 2 \). Keyin \( 2 \log_{2}(x^{2}-2x) = 3 \) tenglamasini yechamiz. Birinchi navbatda, ikkiga bo'lamiz: \(\log_{2}(x^{2}-2x) = \frac{3}{2}\). Keyin bu tenglama eksponent vazifani bajaramiz: \(x^{2}-2x = 2^{\frac{3}{2}} = 2\sqrt{2}\). Bu tenglama \(x^{2}-2x - 2\sqrt{2} = 0\) ko'rinishida ifodalanadi va u yechimini kvadrat formulasi yordamida topamiz. Natijalari −4 va 2 bo'ladi, shuning uchun yechimlar: \(-2; 4\).

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