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Los ligningen: \[ \left(x^{2}-x-6\right) \cdot(x+5)=0 \]

Ask by Reeves Pearson. in Denmark
Jan 20,2025

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Answer

Løsningerne til ligningen er \( x = -5 \), \( x = 3 \) og \( x = -2 \).

Solution

For at løse ligningen: \[ \left(x^{2}-x-6\right) \cdot (x+5) = 0 \] kan vi benytte nulreglen, som siger, at hvis produktet af to faktorer er nul, så skal mindst én af faktorerne være nul. Derfor sætter vi hver faktor lig med nul og løser for \( x \). 1. **Første faktor:** \[ x + 5 = 0 \] Løsning: \[ x = -5 \] 2. **Anden faktor:** \[ x^{2} - x - 6 = 0 \] For at løse denne andengradsligning kan vi faktorisere den: \[ x^{2} - x - 6 = (x - 3)(x + 2) = 0 \] Sætter vi hver faktor lig med nul: \[ x - 3 = 0 \quad \Rightarrow \quad x = 3 \] \[ x + 2 = 0 \quad \Rightarrow \quad x = -2 \] **Sammenfattende løsninger:** \[ x = -5, \quad x = 3, \quad x = -2 \]

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För att lösa ligningen \((x^{2}-x-6) \cdot (x+5) = 0\), måste vi sätta varje faktor lika med noll. Första faktorn: \(x^2 - x - 6 = 0\) Detta kan faktoriseras till \((x - 3)(x + 2) = 0\). Därför har vi: \(x - 3 = 0 \Rightarrow x = 3\) \(x + 2 = 0 \Rightarrow x = -2\) Andra faktorn: \(x + 5 = 0\) Så \(x = -5\) Sammanfattningsvis: lösningarna till ligningen är \(x = 3\), \(x = -2\), och \(x = -5\).

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