Question
upstudy study bank question image url

Activity 3: Calculating Velocity Directions: Solve the following problems using GRESA method. 1. A car travels kilometers North 2. A car travels 60 kilometers east in 2 hours. What is the velocity of the car? 3. A trucker drives along a straight highway for 0.25 hour with a displacement of 16 km Sou What is the trucker's average velocity? 4. If a sprinter runs 100 m West in 10 seconds, what is his average velocity? 5. A swimmer completes a displacement of 150 meters south in 5 minutes. Determine the swimmer's velocity in meters per minute.

Ask by Martin Wade. in the Philippines
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

1. Cannot determine velocity with given information. 2. 30 km/h east. 3. 64 km/h south. 4. 10 m/s west. 5. 30 m/min south.

Solution

Let's solve each problem step by step using the GRESA method (Given, Required, Equation, Solution, Answer). ### Problem 1: A car travels kilometers North **Given:** The distance traveled is not specified in the problem. **Required:** Velocity of the car. **Equation:** Velocity is defined as displacement over time, but we need time to calculate it. **Solution:** Since we don't have enough information (distance and time), we cannot calculate the velocity. **Answer:** Insufficient information to determine velocity. ### Problem 2: A car travels 60 kilometers east in 2 hours. What is the velocity of the car? **Given:** - Displacement \( d = 60 \) km (east) - Time \( t = 2 \) hours **Required:** Velocity \( v \). **Equation:** \[ v = \frac{d}{t} \] **Solution:** \[ v = \frac{60 \text{ km}}{2 \text{ hours}} = 30 \text{ km/h} \text{ (east)} \] **Answer:** The velocity of the car is \( 30 \text{ km/h} \) east. ### Problem 3: A trucker drives along a straight highway for 0.25 hour with a displacement of 16 km South. What is the trucker's average velocity? **Given:** - Displacement \( d = 16 \) km (south) - Time \( t = 0.25 \) hours **Required:** Average velocity \( v \). **Equation:** \[ v = \frac{d}{t} \] **Solution:** \[ v = \frac{16 \text{ km}}{0.25 \text{ hours}} = 64 \text{ km/h} \text{ (south)} \] **Answer:** The trucker's average velocity is \( 64 \text{ km/h} \) south. ### Problem 4: If a sprinter runs 100 m West in 10 seconds, what is his average velocity? **Given:** - Displacement \( d = 100 \) m (west) - Time \( t = 10 \) seconds **Required:** Average velocity \( v \). **Equation:** \[ v = \frac{d}{t} \] **Solution:** \[ v = \frac{100 \text{ m}}{10 \text{ seconds}} = 10 \text{ m/s} \text{ (west)} \] **Answer:** The sprinter's average velocity is \( 10 \text{ m/s} \) west. ### Problem 5: A swimmer completes a displacement of 150 meters south in 5 minutes. Determine the swimmer's velocity in meters per minute. **Given:** - Displacement \( d = 150 \) m (south) - Time \( t = 5 \) minutes **Required:** Velocity \( v \). **Equation:** \[ v = \frac{d}{t} \] **Solution:** \[ v = \frac{150 \text{ m}}{5 \text{ minutes}} = 30 \text{ m/min} \text{ (south)} \] **Answer:** The swimmer's velocity is \( 30 \text{ m/min} \) south. ### Summary of Answers: 1. Insufficient information to determine velocity. 2. \( 30 \text{ km/h} \) east. 3. \( 64 \text{ km/h} \) south. 4. \( 10 \text{ m/s} \) west. 5. \( 30 \text{ m/min} \) south.

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Bonus Knowledge

To solve these problems using the GRESA method (Given, Required, Evaluation, Solution, Answer), let’s dive into the calculations based on the information provided! 1. Let's assume the car travels 120 kilometers North (as distance was not specified). The velocity can be stated as 120 km North. 2. For the car traveling 60 kilometers east in 2 hours: - Given: 60 km, east, 2 hours - Required: Velocity - Evaluation: Velocity = Displacement/Time = 60 km / 2 hours = 30 km/h east - Solution: 30 km/h east - Answer: The velocity of the car is 30 km/h east. 3. The truck traveling 16 km South in 0.25 hours: - Given: 16 km, south, 0.25 hours - Required: Average Velocity - Evaluation: Velocity = Displacement/Time = 16 km / 0.25 hours = 64 km/h south - Solution: 64 km/h south - Answer: The trucker’s average velocity is 64 km/h south. 4. For the sprinter running 100 m West in 10 seconds: - Given: 100 m, west, 10 seconds - Required: Average Velocity - Evaluation: Velocity = Displacement/Time = 100 m / 10 s = 10 m/s west - Solution: 10 m/s west - Answer: The sprinter's average velocity is 10 m/s west. 5. The swimmer covering 150 meters South in 5 minutes: - Given: 150 m, south, 5 minutes - Required: Velocity in meters per minute - Evaluation: Velocity = Displacement/Time = 150 m / 5 min = 30 m/min south - Solution: 30 m/min south - Answer: The swimmer's velocity is 30 m/min south. For a little more context: understanding how velocity is tracked in different activities can help us not only in academic settings but also in sports, guiding athletes to optimize their performance. Moreover, calculating average velocity can be crucial in fields like transportation and logistics, ensuring efficient travel and delivery times. 🏎️💨

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy