Question
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A city council consists of seven Democrats and seven Republicans. If a committee of six
people is selected, find the probability of selecting two Democrats and four Republicans.
(Type a fraction. Simplify your answer.)

Ask by Schmidt Washington. in the United States
Mar 31,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The probability of selecting two Democrats and four Republicans is .

Solution

The total number of ways to form a committee of six people from 14 is
The number of ways to choose exactly 2 Democrats out of 7 is
and the number of ways to choose exactly 4 Republicans out of 7 is
Thus, the number of favorable committees is
The probability is given by
We compute each term:
  1. Compute :
  1. Compute :
Since ,
  1. Compute :
Now, substituting these values, we have
To simplify, notice that both the numerator and the denominator are divisible by 21:
Thus, the simplified probability is

Answered by UpStudy AI and reviewed by a Professional Tutor

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Explain
Simplify this solution

Mind Expander

To solve this problem, we first need to determine the number of ways to choose 2 Democrats from the 7 available and 4 Republicans from the 7 available.
The number of combinations for choosing 2 Democrats is calculated using the binomial coefficient:
Similarly, the number of combinations for choosing 4 Republicans is:
Now, to find the total number of ways to select 2 Democrats and 4 Republicans, we multiply the two results:
Next, we need to calculate the total number of ways to select any 6 people from the entire council of 14 members (7 Democrats + 7 Republicans):
Finally, the probability of selecting 2 Democrats and 4 Republicans is given by the ratio of the favorable outcomes to the total outcomes:
To simplify this fraction, we can find the greatest common divisor (GCD). After testing common factors, we find that both numbers can be divided by 21:
So, the probability of selecting 2 Democrats and 4 Republicans is:

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