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Solve for \( y \). \begin{tabular}{|l}\( -y+5=220 \) \\ \( y=\square \) \\ \( \times \)\end{tabular}

Ask by Pope Tucker. in the United States
Jan 22,2025

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Answer

\( y = -215 \)

Solution

To solve for \( y \) in the equation: \[ -y + 5 = 220 \] Follow these steps: 1. **Subtract 5 from both sides:** \[ -y = 220 - 5 \] \[ -y = 215 \] 2. **Multiply both sides by \(-1\) to solve for \( y \):** \[ y = -215 \] So, the solution is: \[ \begin{tabular}{|l|} \hline \( -y + 5 = 220 \) \\ \( y = -215 \) \\ \(\times\) \\ \hline \end{tabular} \] **Answer:** \( y = -215 \)

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Beyond the Answer

To solve for \( y \) in the equation \( -y + 5 = 220 \), we start by isolating \( y \). First, subtract 5 from both sides: \[ -y = 220 - 5 \] \[ -y = 215 \] Next, to solve for \( y \), we multiply both sides by -1: \[ y = -215 \] So, the solution is \( y = -215 \). If you want to verify this, you can plug \( y \) back into the original equation to check that it satisfies \( -(-215) + 5 = 220 \). And it does!

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