Solve each equation \( 3 \frac{1}{6}-x=2 \frac{2}{3} \)
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First, let's convert those mixed numbers into improper fractions. For \( 3 \frac{1}{6} \), the improper fraction is \( \frac{19}{6} \). For \( 2 \frac{2}{3} \), the improper fraction is \( \frac{8}{3} \). So the equation takes the form: \[ \frac{19}{6} - x = \frac{8}{3} \] To eliminate the fractions, find a common denominator, which is 6. Thus, we can rewrite \( \frac{8}{3} \) as \( \frac{16}{6} \). Now the equation becomes: \[ \frac{19}{6} - x = \frac{16}{6} \] Next, isolate \( x \) by subtracting \( \frac{19}{6} \) from both sides: \[ -x = \frac{16}{6} - \frac{19}{6} \] \[ -x = \frac{-3}{6} \] Which simplifies to: \[ -x = -\frac{1}{2} \] Now, multiply both sides by -1 to solve for \( x \): \[ x = \frac{1}{2} \] So, the solution to the equation is \( x = \frac{1}{2} \).