If the area of a rectangle with width \( x \) can be represented with the expression \( A(x)=x(14-x) \), what is the perimeter of the rectangle? A 28 B 56 C \( 56-4 x \) D \( 4 x+28 \)

To determine the perimeter of the rectangle, let's analyze the given information: 1. **Area Expression**: The area of the rectangle is given by \( A(x) = x(14 - x) \), where \( x \) is the width. 2. **Determine Length**: - Since the area \( A = \text{length} \times \text{width} \), we can express the length as \( \text{length} = 14 - x \). 3. **Calculate Perimeter**: - The perimeter \( P \) of a rectangle is given by: \[ P = 2(\text{length} + \text{width}) = 2((14 - x) + x) = 2 \times 14 = 28 \] Therefore, the perimeter of the rectangle is **28**. **Answer:** A) 28