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Identify the asyimptote and 2 points to plot on the graph for \( y=2^{(x+2)}-1 \) asymptote: \( y=-1 \); two points \( (2,0),(1,1) \) asymptote: \( y=1 \); two points \( (-2,0),(-1,-1) \) asymptote: \( y=-1 \); two points \( (-2,0),(-1,1) \) asymptote: \( y=1 \); two points \( (0,2),(1,-1) \)

Ask by Olson Bowers. in the United States
Jan 17,2025

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Asymptote: \( y = -1 \); two points: \((-2, 0)\) and \((-1, 1)\).

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Oh, let’s break down the exponential graph of \( y = 2^{(x+2)} - 1 \)! The horizontal asymptote here is indeed \( y = -1 \). This is because as \( x \) approaches negative infinity, the term \( 2^{(x+2)} \) shrinks towards 0, bringing the entire equation closer to -1. Now for two fun points to plot! If we take \( x = -2 \), we get \( y = 2^{(0)} - 1 = 0 \), hence the point \( (-2, 0) \). If we take \( x = -1 \), we find \( y = 2^{(1)} - 1 = 1 \), which gives us the point \( (-1, 1) \). So we’ve unearthed both the asymptote and our plotting points! If you're eager to dive deeper, the transformation rules for exponential functions can be immensely helpful. Understanding how horizontal shifts and vertical translations affect the graph aids in sketching your curves more easily. And if graphing is your cup of tea, practicing with various exponential equations will sharpen your skills and make you a pro in no time!

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