Find the exact length of the midsegment of the trapezoid with the vertices \( S(-2,4), T(-2,-4), U(3,-2), V(13,10) \). The length of the midsegment is
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To find the length of the midsegment of a trapezoid, we first need to identify the lengths of the two bases. Given the vertices \( S(-2,4) \), \( T(-2,-4) \), \( U(3,-2) \), and \( V(13,10) \), we can see that there might be two sets of parallel sides. The points \( S \) and \( T \) have the same x-coordinate, hence they are vertical. The distance between them can be calculated as: \[ ST = |y_2 - y_1| = |-4 - 4| = 8. \] Now for the line segment defined by points \( U \) and \( V \), we calculate the distance \( UV \): \[ UV = \sqrt{(13 - 3)^2 + (10 - (-2))^2} = \sqrt{(10)^2 + (12)^2} = \sqrt{100 + 144} = \sqrt{244} = 2\sqrt{61}. \] In a trapezoid, the midsegment connects the midpoints of the legs. The midsegment \( M \) is also calculated as the average of the lengths of the two bases: \[ M = \frac{ST + UV}{2} = \frac{8 + 2\sqrt{61}}{2} = 4 + \sqrt{61}. \] Thus, the exact length of the midsegment is \[ \boxed{4 + \sqrt{61}}. \]