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Find the exact length of the midsegment of the trapezoid with the vertices \( S(-2,4), T(-2,-4), U(3,-2), V(13,10) \). The length of the midsegment is

Ask by Bryant Maxwell. in the United States
Dec 09,2024

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Answer

The length of the midsegment is \( 4 + \sqrt{61} \).

Solution

To find the length of the midsegment of the trapezoid with vertices \( S(-2,4) \), \( T(-2,-4) \), \( U(3,-2) \), and \( V(13,10) \), we first need to identify the bases of the trapezoid. The midsegment of a trapezoid is the line segment that connects the midpoints of the two bases. The length of the midsegment can be calculated using the formula: \[ \text{Length of midsegment} = \frac{b_1 + b_2}{2} \] where \( b_1 \) and \( b_2 \) are the lengths of the two bases. ### Step 1: Identify the bases We need to determine which pairs of vertices form the bases. The vertices \( S \) and \( T \) are both vertical (same x-coordinate), and the vertices \( U \) and \( V \) are not vertical. We will check if \( ST \) and \( UV \) are parallel. 1. **Base \( ST \)**: - The coordinates are \( S(-2, 4) \) and \( T(-2, -4) \). - The length of \( ST \) is calculated as: \[ \text{Length of } ST = |y_2 - y_1| = |-4 - 4| = 8 \] 2. **Base \( UV \)**: - The coordinates are \( U(3, -2) \) and \( V(13, 10) \). - The length of \( UV \) is calculated as: \[ \text{Length of } UV = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(13 - 3)^2 + (10 - (-2))^2} \] \[ = \sqrt{(10)^2 + (12)^2} = \sqrt{100 + 144} = \sqrt{244} = 2\sqrt{61} \] ### Step 2: Calculate the length of the midsegment Now that we have the lengths of the bases \( ST \) and \( UV \), we can find the length of the midsegment: \[ \text{Length of midsegment} = \frac{8 + 2\sqrt{61}}{2} = 4 + \sqrt{61} \] Thus, the exact length of the midsegment of the trapezoid is: \[ \boxed{4 + \sqrt{61}} \]

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To find the length of the midsegment of a trapezoid, we first need to identify the lengths of the two bases. Given the vertices \( S(-2,4) \), \( T(-2,-4) \), \( U(3,-2) \), and \( V(13,10) \), we can see that there might be two sets of parallel sides. The points \( S \) and \( T \) have the same x-coordinate, hence they are vertical. The distance between them can be calculated as: \[ ST = |y_2 - y_1| = |-4 - 4| = 8. \] Now for the line segment defined by points \( U \) and \( V \), we calculate the distance \( UV \): \[ UV = \sqrt{(13 - 3)^2 + (10 - (-2))^2} = \sqrt{(10)^2 + (12)^2} = \sqrt{100 + 144} = \sqrt{244} = 2\sqrt{61}. \] In a trapezoid, the midsegment connects the midpoints of the legs. The midsegment \( M \) is also calculated as the average of the lengths of the two bases: \[ M = \frac{ST + UV}{2} = \frac{8 + 2\sqrt{61}}{2} = 4 + \sqrt{61}. \] Thus, the exact length of the midsegment is \[ \boxed{4 + \sqrt{61}}. \]

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