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\( 1 \leftarrow \begin{array}{l}\text { a. Rewnte the given equation } 5 x+7 y-35=0 \\ \text { slope-intercept form } \\ \text { b. Give the slope and } y \text {-intercept. } \\ \text { c Use the slope and } y \text {-intercept to graph the linear } \\ \text { function } \\ \text { a. The slope-intercept form of the equation is } \\ y=-\frac{5}{7} x+5 \\ \text { (Simplify your answer Use integers or fractions for any } \\ \text { numbers in the equation ) } \\ \text { b. The slope of the equation of the line is } \square \text { and } \\ \text { the } y \text {-intercept is } \square \\ \text { (Type integers or fractions ) }\end{array} \)

Ask by Wright Conner. in the United States
Jan 25,2025

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Answer

a. The slope-intercept form of the equation is \( y = -\frac{5}{7}x + 5 \). b. The slope of the equation of the line is \(-\frac{5}{7}\) and the y-intercept is \(5\). c. To graph the linear function, plot the y-intercept at \((0, 5)\) and use the slope to find another point, such as \((7, 0)\), then draw a straight line through these points.

Solution

Let's solve the problem step by step. ### a. Rewrite the given equation in slope-intercept form The given equation is: \[ 5x + 7y - 35 = 0 \] To convert this to slope-intercept form \(y = mx + b\), we need to isolate \(y\). 1. Start by moving \(5x\) and \(-35\) to the other side: \[ 7y = -5x + 35 \] 2. Now, divide every term by \(7\) to solve for \(y\): \[ y = -\frac{5}{7}x + 5 \] So, the slope-intercept form of the equation is: \[ y = -\frac{5}{7}x + 5 \] ### b. Identify the slope and y-intercept From the slope-intercept form \(y = mx + b\): - The slope \(m\) is \(-\frac{5}{7}\). - The y-intercept \(b\) is \(5\). Thus, we have: - The slope of the equation of the line is \(-\frac{5}{7}\). - The y-intercept is \(5\). ### c. Use the slope and y-intercept to graph the linear function To graph the linear function: 1. **Plot the y-intercept**: Start at the point \((0, 5)\) on the y-axis. 2. **Use the slope**: The slope \(-\frac{5}{7}\) means that for every \(7\) units you move to the right (positive direction on the x-axis), you move \(5\) units down (negative direction on the y-axis). From the point \((0, 5)\): - Move \(7\) units to the right to \(x = 7\). - Move \(5\) units down to \(y = 0\). This gives you the point \((7, 0)\). 3. **Draw the line**: Connect the points \((0, 5)\) and \((7, 0)\) with a straight line, extending it in both directions. ### Summary of Answers - a. The slope-intercept form of the equation is \(y = -\frac{5}{7}x + 5\). - b. The slope of the equation of the line is \(-\frac{5}{7}\) and the y-intercept is \(5\).

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The Deep Dive

To convert the given equation \(5x + 7y - 35 = 0\) into slope-intercept form (y = mx + b), you'll want to isolate \(y\). Start by moving \(5x\) to the other side: \(7y = -5x + 35\). Now divide every term by 7 to solve for \(y\). This gives you \(y = -\frac{5}{7}x + 5\). The slope-intercept form of the equation is indeed \(y = -\frac{5}{7}x + 5\). In this equation, the slope (m) is \(-\frac{5}{7}\) and the y-intercept (b) is \(5\). Now, to graph this linear function, start at the y-intercept \( (0, 5) \). From there, use the slope to determine another point: for every 7 units you move right (positive x-direction), move down 5 units (negative y-direction). This will give you a second point on the graph at \( (7, 0) \). Connect these points with a straight line, and voilà, you've graphed the function!

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