\( 1 \leftarrow \begin{array}{l}\text { a. Rewnte the given equation } 5 x+7 y-35=0 \\ \text { slope-intercept form } \\ \text { b. Give the slope and } y \text {-intercept. } \\ \text { c Use the slope and } y \text {-intercept to graph the linear } \\ \text { function } \\ \text { a. The slope-intercept form of the equation is } \\ y=-\frac{5}{7} x+5 \\ \text { (Simplify your answer Use integers or fractions for any } \\ \text { numbers in the equation ) } \\ \text { b. The slope of the equation of the line is } \square \text { and } \\ \text { the } y \text {-intercept is } \square \\ \text { (Type integers or fractions ) }\end{array} \)
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The Deep Dive
To convert the given equation \(5x + 7y - 35 = 0\) into slope-intercept form (y = mx + b), you'll want to isolate \(y\). Start by moving \(5x\) to the other side: \(7y = -5x + 35\). Now divide every term by 7 to solve for \(y\). This gives you \(y = -\frac{5}{7}x + 5\). The slope-intercept form of the equation is indeed \(y = -\frac{5}{7}x + 5\). In this equation, the slope (m) is \(-\frac{5}{7}\) and the y-intercept (b) is \(5\). Now, to graph this linear function, start at the y-intercept \( (0, 5) \). From there, use the slope to determine another point: for every 7 units you move right (positive x-direction), move down 5 units (negative y-direction). This will give you a second point on the graph at \( (7, 0) \). Connect these points with a straight line, and voilà, you've graphed the function!