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Simplify the algebraic expression \( \frac{x^{2}-2 x y+y^{2}}{\frac{x}{y}-\frac{y}{x}} \) \( \frac{x^{2}-2 x y+y^{2}}{\frac{x}{y}-\frac{y}{x}}=\square \)

Ask by Mcdonald Parry. in the United States
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ \frac{xy(x - y)}{x + y} \]

Solution

To simplify the algebraic expression: \[ \frac{x^{2} - 2xy + y^{2}}{\frac{x}{y} - \frac{y}{x}} \] **Step 1: Factor the Numerator and Denominator** 1. **Numerator:** \(x^{2} - 2xy + y^{2}\) can be factored as: \[ (x - y)^2 \] 2. **Denominator:** \(\frac{x}{y} - \frac{y}{x}\) can be rewritten with a common denominator: \[ \frac{x^2 - y^2}{xy} = \frac{(x - y)(x + y)}{xy} \] **Step 2: Rewrite the Expression** Substitute the factored forms back into the original expression: \[ \frac{(x - y)^2}{\frac{(x - y)(x + y)}{xy}} = (x - y)^2 \times \frac{xy}{(x - y)(x + y)} \] **Step 3: Simplify by Canceling Common Terms** Cancel out one \((x - y)\) from the numerator and denominator: \[ (x - y) \times \frac{xy}{x + y} = \frac{xy(x - y)}{x + y} \] **Final Simplified Expression:** \[ \frac{xy(x - y)}{x + y} \] **Answer:** \[ \frac{xy(x - y)}{\,x + y\,} \]

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Bonus Knowledge

To simplify the algebraic expression \( \frac{x^{2}-2 x y+y^{2}}{\frac{x}{y}-\frac{y}{x}} \), let's first simplify the denominator. The denominator, \( \frac{x}{y}-\frac{y}{x} \), can be combined over a common denominator: \[ \frac{x^2 - y^2}{xy} \] Next, the expression for the numerator, \( x^{2}-2xy+y^{2} \), is a perfect square trinomial that can be factored: \[ (x - y)^2 \] Now we can rewrite the original expression: \[ \frac{(x - y)^2}{\frac{x^2 - y^2}{xy}} = (x - y)^2 \cdot \frac{xy}{x^2 - y^2} \] Notice that \( x^2 - y^2 \) can also be factored as \( (x - y)(x + y) \): \[ = (x - y)^2 \cdot \frac{xy}{(x - y)(x + y)} = \frac{(x - y)xy}{x + y} \] So the simplified expression is: \[ \frac{(x - y)xy}{x + y} \]

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