$$ 6 \mathrm{Ca}+\mathrm{P}_{4} \rightarrow 2 \mathrm{Ca}_{3} \mathrm{P}_{2} $$ Write the complete and balanced equation for the decomposition of HCl . $$ 2 \mathrm{HCl} \longrightarrow \mathrm{H}_{2}+\mathrm{Cl}_{2} $$

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The decomposition of hydrogen chloride (HCl) can be represented by the following balanced chemical equation:

$$
2 \, \mathrm{HCl} \, (g) \rightarrow \mathrm{H}_2 \, (g) + \mathrm{Cl}_2 \, (g)
$$

**Explanation:**

1. **Balancing the Equation:**
   - **Hydrogen (H):** There are 2 hydrogen atoms on the left side (from 2 HCl) and 2 hydrogen atoms on the right side (from H₂).
   - **Chlorine (Cl):** There are 2 chlorine atoms on the left side (from 2 HCl) and 2 chlorine atoms on the right side (from Cl₂).

2. **State Symbols:**
   - **(g)** denotes that the substances are in the gaseous state under the conditions of the reaction.

3. **Reaction Conditions:**
   - The decomposition of HCl typically requires high temperatures to proceed, as HCl is a stable gas under normal conditions.

**Summary:**

$$
2 \, \mathrm{HCl} \, (g) \rightarrow \mathrm{H}_2 \, (g) + \mathrm{Cl}_2 \, (g)
$$

This equation shows that two molecules of hydrogen chloride gas decompose to form one molecule of hydrogen gas and one molecule of chlorine gas.
The balanced equation for the decomposition of HCl is: $$ 2 \, \mathrm{HCl} \, (g) \rightarrow \mathrm{H}_2 \, (g) + \mathrm{Cl}_2 \, (g) $$

\[ 6 \mathrm{Ca}+\mathrm{P}_{4} \rightarrow 2 \mathrm{Ca}_{3} \mathrm{P}_{2} \] Write the complete and balanced equation for the decomposition of HCl . \( 2 \mathrm{HCl} \longrightarrow \mathrm{H}_{2}+\mathrm{Cl}_{2} \)

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